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Study the pattern below and answer the question that follows. Draw a table to represent stage 1 to stage 5. Describe the pattern in Question 7.1 in your own words

Mathematics

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2 parts
8.1

\textbf{T_n = 3n + 2}

8.2

62\textbf{62}

Step-by-step solution

8 steps

Part 7.1· 3 steps

  1. Analyze the pattern to determine the number of shaded diamonds at each stage.

    • Stage 1: 2 shaded diamonds
    • Stage 2: 4 shaded diamonds
    • Stage 3: 6 shaded diamonds
    • Stage 4: 8 shaded diamonds The number of shaded diamonds increases by 2 for each subsequent stage. This means the number of diamonds is 2×stage number2 \times \text{stage number}.
  2. Calculate the number of shaded diamonds for stage 5.

    For stage 5, the number of diamonds will be 2×5=102 \times 5 = 10.

  3. Create the table.

    StageNumber of Shaded Diamonds12243648510\begin{array}{|c|c|} \hline \textbf{Stage} & \textbf{Number of Shaded Diamonds} \\ \hline 1 & 2 \\ \hline 2 & 4 \\ \hline 3 & 6 \\ \hline 4 & 8 \\ \hline 5 & 10 \\ \hline \end{array}

Part 7.2

The pattern shows that the number of shaded diamonds increases by two for each new stage. Specifically, the number of shaded diamonds is always double the stage number.

Part 8.1

\textbf{T_n = 3n + 2}

  1. Find the common difference between consecutive terms in the sequence.

    The given numbers are 5, 8, 11, 14.
    The differences are:
    8−5=38 - 5 = 3
    11−8=311 - 8 = 3
    14−11=314 - 11 = 3
    The common difference d=3d = 3.

  2. Use the formula for the nn-th term of an arithmetic sequence, Tn=a+(n−1)dT_n = a + (n-1)d, where aa is the first term and dd is the common difference.

    Here, a=5a = 5 and d=3d = 3.
    Substitute these values into the formula:

    Tn=5+(n−1)3T_n = 5 + (n-1)3
  3. Simplify the expression to find the relationship.

    Tn=5+3n−3T_n = 5 + 3n - 3 Tn=3n+2T_n = 3n + 2

    The relationship is \boxed{\textbf{T_n = 3n + 2}}.

Part 8.2

62\textbf{62}

  1. Use the rule found in question 8.1, which is Tn=3n+2T_n = 3n + 2.

    We need to find the 20th20^{th} number, so substitute n=20n = 20 into the rule.

    T20=3(20)+2T_{20} = 3(20) + 2
  2. Calculate the value of T20T_{20}.

    T20=60+2T_{20} = 60 + 2 T20=62T_{20} = 62

    The 20th20^{th} number is 62\boxed{\textbf{62}}.

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