This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
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Welcome back Rehema — missed you this week. Here are the solutions to your questions. Question 5: Subtract 4 m 75 cm from 10 m 50 cm. Step 1: Write the subtraction problem, aligning meters and centimeters. c 10 m 50 cm \\ - 4 m 75 cm \\ Step 2: Since 50 cm is less than 75 cm, borrow 1 m from 10 m. 1 m = 100 cm. The 10 m becomes 9 m, and 50 cm becomes 50 cm + 100 cm = 150 cm. c 9 m 150 cm \\ - 4 m 75 cm \\ Step 3: Subtract the centimeters and then the meters. 150 cm - 75 cm = 75 cm 9 m - 4 m = 5 m c 9 m 150 cm \\ - 4 m 75 cm \\ 5 m 75 cm The result is 5m 75cm. Question 1: For each of the following fractions, list other fractions which are equal. To find equivalent fractions, multiply both the numerator and the denominator by the same non-zero integer. a) (4)/(7) Step 1: Multiply the numerator and denominator by 2. (4 × 2)/(7 × 2) = (8)/(14) Step 2: Multiply the numerator and denominator by 3. (4 × 3)/(7 × 3) = (12)/(21) Two equivalent fractions are (8)/(14), (12)/(21). b) (1)/(11) Step 1: Multiply the numerator and denominator by 2. (1 × 2)/(11 × 2) = (2)/(22) Step 2: Multiply the numerator and denominator by 3. (1 × 3)/(11 × 3) = (3)/(33) Two equivalent fractions are (2)/(22), (3)/(33). c) (2)/(9) Step 1: Multiply the numerator and denominator by 2. (2 × 2)/(9 × 2) = (4)/(18) Step 2: Multiply the numerator and denominator by 3. (2 × 3)/(9 × 3) = (6)/(27) Two equivalent fractions are (4)/(18), (6)/(27). Drop the next question!