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Calculate the symmetric difference between sets A = 1, 2, 3 and B = 3, 4, 5.

Mathematics

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Answer

{1,2,4,5}\{1, 2, 4, 5\}

Step-by-step solution

5 steps
  1. Understand the definition of symmetric difference.

    The symmetric difference of two sets AA and BB, denoted as AΔBA \Delta B, is the set of elements that are in either AA or BB, but not in their intersection. It can be calculated using the formula:

    AΔB=(A−B)∪(B−A)A \Delta B = (A - B) \cup (B - A)

    or equivalently:

    AΔB=(A∪B)−(A∩B)A \Delta B = (A \cup B) - (A \cap B)
  2. Identify the given sets.

    Given:
    A={1,2,3}A = \{1, 2, 3\}
    B={3,4,5}B = \{3, 4, 5\}

  3. Calculate A−BA - B.

    A−BA - B contains elements that are in AA but not in BB.

    A−B={1,2,3}−{3,4,5}={1,2}A - B = \{1, 2, 3\} - \{3, 4, 5\} = \{1, 2\}
  4. Calculate B−AB - A.

    B−AB - A contains elements that are in BB but not in AA.

    B−A={3,4,5}−{1,2,3}={4,5}B - A = \{3, 4, 5\} - \{1, 2, 3\} = \{4, 5\}
  5. Calculate the union of (A−B)(A - B) and (B−A)(B - A).

    AΔB=(A−B)∪(B−A)A \Delta B = (A - B) \cup (B - A) AΔB={1,2}∪{4,5}A \Delta B = \{1, 2\} \cup \{4, 5\} AΔB={1,2,4,5}A \Delta B = \{1, 2, 4, 5\}

    The symmetric difference between A and B is {1,2,4,5}\boxed{\{1, 2, 4, 5\}}.

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