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Thabo bought a car for R65 000. He spent R12 575 on the car to ensure that it is in good condition. He then sold the car for R110 000. How much profit did he receive?

Mathematics

ScanSolve AI Answer

Answer

A

Step-by-step solution

6 steps

Here are the solutions for the questions from your Grade 7 Mathematics test:

Section A

Part 1.1· 4 steps

Arrange the above numbers in ascending order.

The given numbers are: 123 243 645123\,243\,645; 123 243 546123\,243\,546; 123 243 654123\,243\,654; 123 243 465123\,243\,465.

  1. Compare the numbers by looking at their digits from left to right.

    All numbers share the same first six digits (123 243123\,243).

  2. Compare the last three digits of each number

    645, 546, 654, 465.

  3. Arrange these last three-digit numbers in ascending order

    465, 546, 645, 654.

  4. Combine these with the common prefix to get the full numbers in ascending order.

    The numbers in ascending order are:
    123 243 465123\,243\,465; 123 243 546123\,243\,546; 123 243 645123\,243\,645; 123 243 654123\,243\,654.

    Comparing this with the given options, the correct option is A.

    A\boxed{\text{A}}

Part 1.2· 2 steps

Thabo bought a car for R65 000. He spent R12 575 on the car to ensure that it is in good condition. He then sold the car for R110 000. How much profit did he receive?

  1. Calculate the total cost Thabo incurred for the car.

    Total Cost=Purchase Price+Repair Cost\text{Total Cost} = \text{Purchase Price} + \text{Repair Cost} Total Cost=R65 000+R12 575\text{Total Cost} = \text{R}65\,000 + \text{R}12\,575 Total Cost=R77 575\text{Total Cost} = \text{R}77\,575
  2. Calculate the profit by subtracting the total cost from the selling price.

    Profit=Selling Price−Total Cost\text{Profit} = \text{Selling Price} - \text{Total Cost} Profit=R110 000−R77 575\text{Profit} = \text{R}110\,000 - \text{R}77\,575 Profit=R32 425\text{Profit} = \text{R}32\,425

    Comparing this with the given options, the correct option is B.

    B\boxed{\text{B}}
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