Here are the solutions to the problems.
Question 9:
a) Prove that 1−sinθcosθ=secθ+tanθ.
Step 1: Start with the left-hand side (LHS) of the equation.
LHS=1−sinθcosθ
Step 2: Multiply the numerator and denominator by the conjugate of the denominator, which is 1+sinθ.
LHS=1−sinθcosθ×1+sinθ1+sinθ