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The area of a triangle is X cm2. If its base is Y cm, what is its height?

Mathematics

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2 parts
39

10 cm\text{10 cm}

40

8 cm\text{8 cm}

Step-by-step solution

8 steps

Here are the solutions to the problems from the image.

** (unnumbered):**
The area of a triangle is 36 cm236 \text{ cm}^2. If its base is 6 cm6 \text{ cm}, what is its height?

Step 1: Write the formula for the area of a triangle.
The area of a triangle (AA) is given by:

A=12bhA = \frac{1}{2}bh

where bb is the base and hh is the height.

Step 2: Substitute the given values into the formula.
Given A=36 cm2A = 36 \text{ cm}^2 and b=6 cmb = 6 \text{ cm}.

36=12×6×h36 = \frac{1}{2} \times 6 \times h

Step 3: Solve for the height (hh).

36=3h36 = 3h h=363h = \frac{36}{3} h=12 cmh = 12 \text{ cm}

The height of the triangle is 12 cm\boxed{\text{12 cm}}.


Part 39· 3 steps

The area of a triangle is 100 cm2100 \text{ cm}^2. If its base is 20 cm20 \text{ cm}, what is its height?

  1. Write the formula for the area of a triangle.

    A=12bhA = \frac{1}{2}bh
  2. Substitute the given values into the formula.

    Given A=100 cm2A = 100 \text{ cm}^2 and b=20 cmb = 20 \text{ cm}.

    100=12×20×h100 = \frac{1}{2} \times 20 \times h
  3. Solve for the height (hh).

    100=10h100 = 10h h=10010h = \frac{100}{10} h=10 cmh = 10 \text{ cm}

    The height of the triangle is 10 cm\boxed{\text{10 cm}}.


Part 40

8 cm\text{8 cm}

The area of a triangle is 32 cm232 \text{ cm}^2. If its base is 8 cm8 \text{ cm}, what is its height?

  1. Write the formula for the area of a triangle.

    A=12bhA = \frac{1}{2}bh
  2. Substitute the given values into the formula.

    Given A=32 cm2A = 32 \text{ cm}^2 and b=8 cmb = 8 \text{ cm}.

    32=12×8×h32 = \frac{1}{2} \times 8 \times h
  3. Solve for the height (hh).

    32=4h32 = 4h h=324h = \frac{32}{4} h=8 cmh = 8 \text{ cm}

    The height of the triangle is 8 cm\boxed{\text{8 cm}}.


Part 41· 2 steps

The side of a square field is 40 cm40 \text{ cm}. Find its perimeter and area.

  1. Write the formulas for the perimeter and area of a square.

    For a square with side length ss:
    Perimeter (PP) = 4s4s
    Area (AA) = s2s^2

  2. Substitute the given side length into the formulas.

    Given s=40 cms = 40 \text{ cm}.
    Perimeter: P=4×40 cmP = 4 \times 40 \text{ cm}
    Area: $A = (40 cm)^

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