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In the shapes below, work out the ratio of the area of the original shape to the area of the enlarged shape.

Mathematics

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Here are the solutions to the problems:

1. a)

  1. Identify the given dimensions of the original rectangle.

    The length is 2 cm2 \text{ cm} and the width is 1 cm1 \text{ cm}.

  2. Calculate the area of the original rectangle using the formula Area=length×widthArea = length \times width.

    A1=2 cm×1 cm=2 cm2A_1 = 2 \text{ cm} \times 1 \text{ cm} = 2 \text{ cm}^2

    The area of the original rectangle is 2 cm2\boxed{\text{2 cm}^2}.

    1. b)

  3. Assume an enlargement factor.

    The problem does not explicitly state the enlargement factor for the rectangle. Based on the context of the exercise and the following question (Q2) which uses an enlargement factor of 4, we will assume the rectangle is also enlarged by a factor of k=4k=4.

  4. Calculate the new length and width of the larger rectangle.

    New length L2=2 cm×4=8 cmL_2 = 2 \text{ cm} \times 4 = 8 \text{ cm}
    New width W2=1 cm×4=4 cmW_2 = 1 \text{ cm} \times 4 = 4 \text{ cm}

  5. Calculate the area of the larger rectangle.

    A2=8 cm×4 cm=32 cm2A_2 = 8 \text{ cm} \times 4 \text{ cm} = 32 \text{ cm}^2

    The area of the larger rectangle is 32 cm2\boxed{\text{32 cm}^2}.

    2.
    To draw the letter N and enlarge it by a factor of 4:

  6. Observe the original letter N on the grid.

    It is 3 units high and 3 units wide (from the leftmost point to the rightmost point). The vertical segments are 3 units long, and the diagonal segment spans 2 units horizontally and 2 units vertically.

  7. Multiply all dimensions by the enlargement factor of 4.

    • The vertical segments will become 3×4=123 \times 4 = 12 units long.
    • The horizontal span of the letter will become 3×4=123 \times 4 = 12 units.
    • The horizontal projection of the diagonal will become 2×4=82 \times 4 = 8 units.
    • The vertical projection of the diagonal will become 2×4=82 \times 4 = 8 units.
  8. Draw the enlarged letter N on squared paper using these new dimensions.

    For example, if the bottom-left point of the original N is at (0,0), the enlarged N would have its bottom-left point at (0,0), its top-left point at (0,12), its bottom-right point at (12,0), and its top-right point at (12,12). The diagonal would connect (0,12) to (12,0).

    3.

  9. Identify the original radius and the factor of reduction.

    Original radius r1=10 cmr_1 = 10 \text{ cm}.
    Factor of reduction k=12k = \frac{1}{2}.

  10. Calculate the radius of the smaller circle.

    r2=r1×k=10 cm×12=5 cmr_2 = r_1 \times k = 10 \text{ cm} \times \frac{1}{2} = 5 \text{ cm}

    The radius of the smaller circle is 5 cm\boxed{\text{5 cm}}.

    4.

  11. Identify the original perimeter and the factor of enlargement.

    Original perimeter P1=12 cmP_1 = 12 \text{ cm}.
    Factor of enlargement k=2k = 2.

  12. Calculate the perimeter of the larger square.

    P2=P1×k=12 cm×2=24 cmP_2 = P_1 \times k = 12 \text{ cm} \times 2 = 24 \text{ cm}

    The perimeter of the larger square is 24 cm\boxed{\text{24 cm}}.

    5.

  13. Identify the original perimeter and the factor of reduction.

    Original perimeter P1=24 cmP_1 = 24 \text{ cm}.
    Factor of reduction k=13k = \frac{1}{3}.

  14. Calculate the perimeter of the smaller square.

    P2=P1×k=24 cm×13=8 cmP_2 = P_1 \times k = 24 \text{ cm} \times \frac{1}{3} = 8 \text{ cm}

    The perimeter of the smaller square is 8 cm\boxed{\text{8 cm}}.

    6. a)

  15. Calculate the area of the original rectangle (solid lines).

    Length = 2 units, Width = 1 unit.

    Aoriginal=2×1=2 square unitsA_{\text{original}} = 2 \times 1 = 2 \text{ square units}
  16. Calculate the area of the enlarged rectangle (dashed lines).

    Length = 4 units, Width = 2 units.

    Aenlarged=4×2=8 square unitsA_{\text{enlarged}} = 4 \times 2 = 8 \text{ square units}
  17. Determine the ratio of the area of the original shape to the area of the enlarged shape.

    Aoriginal:Aenlarged=2:8=1:4A_{\text{original}} : A_{\text{enlarged}} = 2 : 8 = \boxed{1 : 4}

    6. b)

  18. Calculate the area of the original triangle (solid lines).

    Base = 2 units, Height = 2 units.

    Aoriginal=12×base×height=12×2×2=2 square unitsA_{\text{original}} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 2 \times 2 = 2 \text{ square units}
  19. Calculate the area of the enlarged triangle (dashed lines).

    Base = 4 units, Height = 4 units.

    Aenlarged=12×base×height=12×4×4=8 square unitsA_{\text{enlarged}} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 4 \times 4 = 8 \text{ square units}
  20. Determine the ratio of the area of the original shape to the area of the enlarged shape.

    Aoriginal:Aenlarged=2:8=1:4A_{\text{original}} : A_{\text{enlarged}} = 2 : 8 = \boxed{1 : 4}

    7.
    To draw these shapes and enlarge them by a factor of 2:
    For each shape, identify the coordinates of its vertices (or key dimensions like base and height). Multiply each coordinate or dimension by the enlargement factor of 2 to get the new coordinates or dimensions for the enlarged shape. Then, draw the new shape on squared paper.

    7. a) Parallelogram:

    • Original: Base is 3 units, height is 1 unit. The top-left vertex is 1 unit to the right of the bottom-left vertex.
    • Enlarged: Base will be 3×2=63 \times 2 = 6 units, height will be 1×2=21 \times 2 = 2 units. The top-left vertex will be 1×2=21 \times 2 = 2 units to the right of the bottom-left vertex.

    7. b) Kite:

    • Original: Vertices can be identified relative to a grid. For example, if the bottom vertex is at (2,0), the other vertices are (0,2), (2,4), (4,2).
    • Enlarged: Multiply all coordinates by 2. The new vertices would be (4,0), (0,4), (4,8), (8,4).

    7. c) Irregular quadrilateral:

    • Original: Vertices can be identified. For example, (0,0), (4,0), (5,2), (1,2).
    • Enlarged: Multiply all coordinates by 2. The new vertices would be (0,0), (8,0), (10,4), (2,4).

    8.
    To find the factor of enlargement or reduction, compare corresponding lengths between the two shapes. We will assume the smaller shape is the original and the larger shape is the image, thus determining an enlargement factor.

    8. a) Kite:

  21. Measure a corresponding length on the smaller (dashed) kite.

    The vertical diagonal of the dashed kite is 2 units long.

  22. Measure the corresponding length on the larger (solid) kite.

    The vertical diagonal of the solid kite is 4 units long.

  23. Calculate the factor of enlargement.

    k=Length of imageLength of original=42=2k = \frac{\text{Length of image}}{\text{Length of original}} = \frac{4}{2} = 2

    The factor of enlargement is 2\boxed{2}.

    8. b) Triangle:

  24. Measure a corresponding length on the smaller (dashed) triangle.

    The base of the dashed triangle is 1 unit long.

  25. Measure the corresponding length on the larger (solid) triangle.

    The base of the solid triangle is 3 units long.

  26. Calculate the factor of enlargement.

    k=Length of imageLength of original=31=3k = \frac{\text{Length of image}}{\text{Length of original}} = \frac{3}{1} = 3

    The factor of enlargement is 3\boxed{3}.

    8. c) Triangle:

  27. Measure a corresponding length on the smaller (solid) triangle.

    The base of the solid triangle is 1 unit long.

  28. Measure the corresponding length on the larger (dashed) triangle.

    The base of the dashed triangle is 4 units long.

  29. Calculate the factor of enlargement.

    k=Length of imageLength of original=41=4k = \frac{\text{Length of image}}{\text{Length of original}} = \frac{4}{1} = 4

    The factor of enlargement is 4\boxed{4}.

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