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What is the area of the composite shape shown with sides 10m, 13m, 5m, and 12m?

Mathematics

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Step-by-step solution

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The image shows a right trapezoid with the following dimensions:

  • Parallel sides: 10 m10 \text{ m} and 5 m5 \text{ m}
  • Height (perpendicular distance between parallel sides): 12 m12 \text{ m}
  • Slanted side: 13 m13 \text{ m}

Since no specific question was asked, I will calculate both the perimeter and the area of this shape.

  1. Calculate the perimeter.

    The perimeter is the sum of all four sides of the trapezoid.

    P=10 m+12 m+5 m+13 mP = 10 \text{ m} + 12 \text{ m} + 5 \text{ m} + 13 \text{ m} P=40 mP = 40 \text{ m}
  2. Calculate the area.

    The area of a trapezoid is given by the formula A=12(a+b)hA = \frac{1}{2} (a+b)h, where aa and bb are the lengths of the parallel sides and hh is the perpendicular height between them.

    A=12(10 m+5 m)×12 mA = \frac{1}{2} (10 \text{ m} + 5 \text{ m}) \times 12 \text{ m} A=12(15 m)×12 mA = \frac{1}{2} (15 \text{ m}) \times 12 \text{ m} A=15 m×6 mA = 15 \text{ m} \times 6 \text{ m} A=90 m2A = 90 \text{ m}^2

    The perimeter of the trapezoid is 40 m\boxed{40 \text{ m}}.
    The area of the trapezoid is 90 m2\boxed{90 \text{ m}^2}.

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