The curve y = 2x(3−x) crosses the x-axis at O and B. The line y = 2x − 2 intersects the curve at points P and Q. Find the coordinates of O, B, P, Q and the area enclosed by the curve and the line.

It appears that Question 6 is partially cut off in the image. Based on the visible information and typical questions associated with such graphs, I will provide a comprehensive solution covering the likely parts of the question.

Assumed Question 6:
The curve with the equation $y = 2x(3-x)$ crosses the $x$-axis at $O$ and $B$. The line $y = 2x - 2$ intersects the curve at points $P$ and $Q$.

• a) Find the coordinates of $O$ and $B$.
• b) Find the coordinates of $P$ and $Q$.
• c) Find the area of the region enclosed by the curve and the line.

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Solution for Question 6:

Part a): Find the coordinates of $O$ and $B$.
The curve $y = 2x(3-x)$ crosses the $x$-axis when $y=0$.

$$2x(3-x) = 0$$

This equation holds if $2x = 0$ or $3-x = 0$.

$$x = 0 \quad \text{or} \quad x = 3$$

Since $O$ is the origin, its coordinates are $(0,0)$.
The other point $B$ has coordinates $(3,0)$.
The coordinates are $\boxed{O=(0,0), B=(3,0)}$.

Part b): Find the coordinates of $P$ and $Q$.
To find the intersection points of the curve $y = 2x(3-