This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
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Hey God, good to see you again. Here's the solution for question 6: a) Find the area of triangle FGH Step 1: Determine the base of triangle FGH. The figure DEFH is a parallelogram, so DH = EF = 4.8 cm. The total base DG = 10.2 cm. The base of triangle FGH is HG = DG - DH. HG = 10.2 cm - 4.8 cm = 5.4 cm The height of the triangle is 3.3 cm. Step 2: Calculate the area of triangle FGH. The formula for the area of a triangle is (1)/(2) × base × height. Area of FGH = (1)/(2) × HG × height Area of FGH = (1)/(2) × 5.4 cm × 3.3 cm Area of FGH = 2.7 cm × 3.3 cm Area of FGH = 8.91 cm^2 b) Find the area of parallelogram DEFH Step 1: Identify the base and height of parallelogram DEFH. The base of the parallelogram is DH = 4.8 cm. The height of the parallelogram is 3.3 cm. Step 2: Calculate the area of parallelogram DEFH. The formula for the area of a parallelogram is base × height. Area of parallelogram DEFH = DH × height Area of parallelogram DEFH = 4.8 cm × 3.3 cm Area of parallelogram DEFH = 15.84 cm^2 c) What is the sum of the area of triangle and parallelogram DEFH? Step 1: Add the area of triangle FGH and the area of parallelogram DEFH. Sum of areas = Area of FGH + Area of parallelogram DEFH Sum of areas = 8.91 cm^2 + 15.84 cm^2 Sum of areas = 24.75 cm^2 Send me the next one 📸