The first and last terms of an Arithmetic progression (AP) are -3 and 393 respectively. If the progression has 100 terms, find the 33rd term of the AP.

The first term, $a = -3$.
The last term, $L = 393$.
The total number of terms, $n = 100$.
The formula for the $n$-th term is $T_n = a + (n-1)d$, where $d$ is the common difference.

The last term is the 100th term, so $T_{100} = 393$.
Substitute the values into the formula:

Add 3 to both sides:

Divide by 99 to find $d$:

Now that we have the common difference $d=4$, we can find the 33rd term using the formula $T_n = a + (n-1)d$ with $n=33$.

The 33rd term of the AP is $\boxed{125}$.