The following pairs of triangles are similar. Calculate the value of x and/or y in each case.

We can see that 5 m corresponds to 10 m (since $\frac{5}{10} = \frac{1}{2}$) and 7 m corresponds to 14 m (since $\frac{7}{14} = \frac{1}{2}$). Therefore, $x$ must correspond to 16 m.

$$\frac{5}{10} = \frac{x}{16}$$

Simplify the ratio:

$$\frac{1}{2} = \frac{x}{16}$$

Multiply both sides by 16:

$$x = \frac{16}{2}$$ $$x = 8$$

The value of $x$ is $\boxed{\text{8 m}}$.

Since both triangles appear to be isosceles, the equal sides of the smaller triangle (3 cm) correspond to the equal sides of the larger triangle (9 cm). The ratio of similarity is $\frac{3}{9} = \frac{1}{3}$.
Therefore, the third side of the smaller triangle ($y$) must correspond to the third side of the larger triangle (5 cm).

$$\frac{3}{9} = \frac{y}{5}$$

Simplify the ratio:

$$\frac{1}{3} = \frac{y}{5}$$

Multiply both sides by 5:

$$y = \frac{5}{3}$$

The value of $y$ is $\boxed{\frac{5}{3} \text{ cm}}$.