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The functions f and g are defined by f(x) = 2x² and g(x) = (3x−2)/(x+1). Find fog(x).

Mathematics

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Answer

18x2−24x+8x2+2x+1\frac{18x^2 - 24x + 8}{x^2 + 2x + 1}

Step-by-step solution

4 steps
  1. Identify the given functions.

    The functions are defined as:

    f(x)=2x2f(x) = 2x^2 g(x)=3x−2x+1g(x) = \frac{3x-2}{x+1}
  2. Understand the composite function (f∘g)(x)(f \circ g)(x).

    The notation (f∘g)(x)(f \circ g)(x) means f(g(x))f(g(x)). This involves substituting the entire function g(x)g(x) into f(x)f(x) wherever 'x' appears in f(x)f(x).

  3. Substitute g(x)g(x) into f(x)f(x).

    Replace xx in f(x)=2x2f(x) = 2x^2 with g(x)=3x−2x+1g(x) = \frac{3x-2}{x+1}:

    f(g(x))=2(3x−2x+1)2f(g(x)) = 2\left(\frac{3x-2}{x+1}\right)^2
  4. Simplify the expression.

    Square the fraction:

    f(g(x))=2⋅(3x−2)2(x+1)2f(g(x)) = 2 \cdot \frac{(3x-2)^2}{(x+1)^2}

    Expand the numerator (3x−2)2(3x-2)^2 and the denominator (x+1)2(x+1)^2:

    (3x−2)2=(3x)2−2(3x)(2)+(−2)2=9x2−12x+4(3x-2)^2 = (3x)^2 - 2(3x)(2) + (-2)^2 = 9x^2 - 12x + 4 (x+1)2=x2+2(x)(1)+12=x2+2x+1(x+1)^2 = x^2 + 2(x)(1) + 1^2 = x^2 + 2x + 1

    Substitute these expanded forms back into the expression:

    f(g(x))=2⋅9x2−12x+4x2+2x+1f(g(x)) = 2 \cdot \frac{9x^2 - 12x + 4}{x^2 + 2x + 1}

    Multiply the numerator by 2:

    f(g(x))=2(9x2−12x+4)x2+2x+1f(g(x)) = \frac{2(9x^2 - 12x + 4)}{x^2 + 2x + 1} f(g(x))=18x2−24x+8x2+2x+1f(g(x)) = \frac{18x^2 - 24x + 8}{x^2 + 2x + 1}

    The composite function is:

    18x2−24x+8x2+2x+1\frac{18x^2 - 24x + 8}{x^2 + 2x + 1}
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