The graph shows the graph of y = 3−2x−x2 passing through A, B and C. Find the coordinates of A, B and C.

The y-intercept occurs when $x = 0$. Substitute $x = 0$ into the equation:

$$y = 3 - 2(0) - (0)^2$$ $$y = 3 - 0 - 0$$ $$y = 3$$

So, the coordinates of B are $(0, 3)$.

The x-intercepts occur when $y = 0$. Set $y = 0$ in the equation and solve for $x$:

$$0 = 3 - 2x - x^2$$

Rearrange the equation to a standard quadratic form:

$$x^2 + 2x - 3 = 0$$

Factorize the quadratic equation:

$$(x + 3)(x - 1) = 0$$

This gives two possible values for $x$:

$$x + 3 = 0 \implies x = -3$$ $$x - 1 = 0 \implies x = 1$$

From the sketch, point A is on the negative x-axis and point C is on the positive x-axis.
So, the coordinates of A are $(-3, 0)$ and the coordinates of C are $(1, 0)$.

The coordinates are:
A: $\boxed{(-3, 0)}$
B: $\boxed{(0, 3)}$
C: $\boxed{(1, 0)}$