The length of a rectangle is 4cm more than twice it's width .The perimeter of the is 40cm . Formulate an equation to determine the dimensions of the rectangle

Mathematics

ScanSolve AI Answer

Answer

6w+8=406w + 8 = 40

Step-by-step solution

4 steps
  1. Define variables for the dimensions of the rectangle.

    Let ww be the width of the rectangle in cm.
    Let ll be the length of the rectangle in cm.

  2. Express the length in terms of the width using the given information.

    "The length of a rectangle is 4cm more than twice its width."

    l=2w+4l = 2w + 4
  3. Write the formula for the perimeter of a rectangle and substitute the given perimeter.

    The perimeter PP of a rectangle is given by P=2(l+w)P = 2(l + w).
    We are given that the perimeter is 40 cm.

    2(l+w)=402(l + w) = 40
  4. Substitute the expression for ll from Step 2 into the perimeter equation from Step 3 and simplify.

    2((2w+4)+w)=402((2w + 4) + w) = 40 2(3w+4)=402(3w + 4) = 40 6w+8=406w + 8 = 40

    This is the equation to determine the dimensions of the rectangle.

Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp