The length of a swimming pool is 16m and the width is 8m. Using a suitable scale draw the scale length and width and find the area. The height of a building is 40m. Using a scale 1cm rep 5m draw the scale. The length of a door is measured as 400cm. Represent the length of the door.

Tutatumia kipimo cha $1 \text{ cm}$ kuwakilisha $2 \text{ m}$.

$$\text{Kipimo} = 1 \text{ cm} : 2 \text{ m}$$

$$\text{Eneo} = \text{Urefu} \times \text{Upana} = 16 \text{ m} \times 8 \text{ m} = 128 \text{ m}^2$$

Urefu kwenye mchoro ni $8 \text{ cm}$, upana kwenye mchoro ni $4 \text{ cm}$, na eneo halisi ni $\boxed{\text{}128 \text{ m}^2\text{}}$

5. Urefu wa jengo ni $40 \text{ m}$. Kwa kutumia kipimo $1 \text{ cm}$ inawakilisha $5 \text{ m}$, chora kipimo.

• Urefu halisi wa jengo = $40 \text{ m}$
• Kipimo = $1 \text{ cm} : 5 \text{ m}$

$$\text{Urefu kwenye mchoro} = \frac{\text{Urefu halisi}}{\text{Kipimo}} = \frac{40 \text{ m}}{5 \text{ m/cm}} = 8 \text{ cm}$$

Urefu wa jengo kwenye mchoro ni $\boxed{\text{}8 \text{ cm}\text{}}$

6. Urefu wa mlango umepimwa kama $400 \text{ cm}$ kutokana na kwamba $1 \text{ cm}$ inawakilisha $50 \text{ cm}$. Wakilisha urefu wa mlango.

• Urefu halisi wa mlango = $400 \text{ cm}$
• Kipimo = $1 \text{ cm} : 50 \text{ cm}$

$$\text{Urefu kwenye mchoro} = \frac{\text{Urefu halisi}}{\text{Kipimo}} = \frac{400 \text{ cm}}{50 \text{ cm/cm}} = 8 \text{ cm}$$

Urefu wa mlango kwenye mchoro ni $\boxed{\text{}8 \text{ cm}\text{}}$