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The modulus of the complex number (1-2i)/(2+i) is:

Mathematics

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Question 10:
The modulus of the complex number 1−2i2+i\frac{1-2i}{2+i} is:

Step 1: Simplify the complex number by multiplying the numerator and denominator by the conjugate of the denominator.

z=1−2i2+iz = \frac{1-2i}{2+i} z=1−2i2+i×2−i2−iz = \frac{1-2i}{2+i} \times \frac{2-i}{2-i} z=(1)(2)+(1)(−i)+(−2i)(2)+(−2i)(−i)22−i2z = \frac{(1)(2) + (1)(-i) + (-2i)(2) + (-2i)(-i)}{2^2 - i^2}
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