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What is the nth term rule for the pattern: 3, 6, 9, 12, 15,...?

Mathematics

ScanSolve AI Answer

Answer

B

Step-by-step solution

6 steps

To find the nnth term rule for the pattern 3,6,9,12,15,…3, 6, 9, 12, 15, \dots, we first need to determine if it's an arithmetic or geometric sequence.

  1. Find the difference between consecutive terms.

    6−3=36 - 3 = 3
    9−6=39 - 6 = 3
    12−9=312 - 9 = 3
    15−12=315 - 12 = 3
    Since the difference between consecutive terms is constant, this is an arithmetic sequence with a common difference (dd) of 3.

  2. Identify the first term.

    The first term (a1a_1) is 3.

  3. Use the formula for the $n$th term of an arithmetic sequence.

    The formula is an=a1+(n−1)da_n = a_1 + (n-1)d.

  4. Substitute the values of a1a_1 and dd into the formula.

    an=3+(n−1)3a_n = 3 + (n-1)3
  5. Simplify the expression.

    an=3+3n−3a_n = 3 + 3n - 3 an=3na_n = 3n
  6. Verify the rule with a few terms from the pattern.

    For n=1n=1, a1=3(1)=3a_1 = 3(1) = 3
    For n=2n=2, a2=3(2)=6a_2 = 3(2) = 6
    For n=3n=3, a3=3(3)=9a_3 = 3(3) = 9
    The rule an=3na_n = 3n correctly generates the terms of the pattern.

    Comparing this with the given options:
    A. an=n+2a_n = n+2
    B. an=3na_n = 3n
    C. an=3n+1a_n = 3n+1
    D. an=n+3a_n = n+3

    The correct option is B.

    The final answer is B. an=3n\boxed{\text{B. } a_n = 3n}.

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