1.1.1 The opening balance is the amount of money available in the bank account at the beginning of the statement period, which is R9 872.50 on 01/02/2022. 1.1.2 Step 1: Identify the total amount debited for the cellphone account. From the statement, on 02/02/2022, "Debit order- cellphone account" is R289.32. Step 2: Subtract the monthly contract fee from the total debit. $$ \text{Amount spent on calls} = \text{Total cellphone debit} - \text{Monthly contract fee} $$ $$ \text{Amount spent on calls} = \text{R } 289.32 - \text{R } 85.00 $$ $$ \text{Amount spent on calls} = \text{R } 204.32 $$ Solly spent $\boxed{\text{R } 204.32}$ on calls in February. 1.1.3 Step 1: Identify all ATM withdrawal amounts from the statement. On 06/02/2022, ATM Withdrawal = R1 000.00 On 10/02/2022, ATM Withdrawal = R880.00 Step 2: Sum the ATM withdrawal amounts. $$ \text{Total ATM withdrawals} = \text{R } 1000.00 + \text{R } 880.00 $$ $$ \text{Total ATM withdrawals} = \text{R } 1880.00 $$ The total amount Solly withdrew through ATM withdrawals is $\boxed{\text{R } 1880.00}$. 1.1.4 Step 1: Locate the "Debit order - Car insurance" transaction. On 03/02/2022, "Debit order - Car insurance" is R1 000.00. Solly paid $\boxed{\text{R } 1000.00}$ for Car Insurance. 1.1.5 Step 1: Find the closing balance on the 21st of February. On 21/02/2022, after the "Cash deposit at Branch" and its "Transaction Fee", the closing balance is R2 227.96. The closing balance on the 21st of February is $\boxed{\text{R } 2227.96}$. 1.1.6 Step 1: List all bank charges (Transaction Fees and Monthly account fee) from the statement. • 01/02/2022: Transaction Fee = R1.50 • 02/02/2022: Transaction Fee = R6.00 • 02/02/2022: Transaction Fee = R6.00 • 03/02/2022: Transaction Fee = R6.00 • 06/02/2022: Transaction Fee = R6.00 • 10/02/2022: Transaction Fee = R6.00 • 21/02/2022: Transaction Fee = R5.59 • 28/02/2022: Monthly account fee = R8.20 Step 2: Sum all the bank charges. $$ \text{Total bank charges} = 1.50 + 6.00 + 6.00 + 6.00 + 6.00 + 6.00 + 5.59 + 8.20 $$ $$ \text{Total bank charges} = \text{R } 47.29 $$ Solly's total bank charges for the month are $\boxed{\text{R } 47.29}$. 1.2.1 Step 1: Identify the fee structure for "Cash deposit (At the branch)" from Table 1. Fee = R2.50 + 0.95% of value. The deposit value is R325.00. Step 2: Calculate the fee. $$ \text{Fee} = \text{R } 2.50 + (0.0095 \times \text{R } 325.00) $$ $$ \text{Fee} = \text{R } 2.50 + \text{R } 3.0875 $$ $$ \text{Fee} = \text{R } 5.5875 $$ Rounding to two decimal places, the fee is $\boxed{\text{R } 5.59}$. The statement shows R5.59, which matches the calculation. 1.2.2 Step 1: Calculate the fee if the money was deposited at the ATM. From Table 1, "Cash deposit (At ATM)" fee = R0.90 per R100 (or part thereof). The deposit amount is R325.00. Number of R100 parts = $\lceil \frac{325}{100} \rceil = \lceil 3.25 \rceil = 4$ parts. $$ \text{ATM deposit fee} = 4 \times \text{R } 0.90 $$ $$ \text{ATM deposit fee} = \text{R } 3.60 $$ Step 2: Calculate the saving. The fee at the branch was R5.59 (from 1.2.1). $$ \text{Saving} = \text{Branch deposit fee} - \text{ATM deposit fee} $$ $$ \text{Saving} = \text{R } 5.59 - \text{R } 3.60 $$ $$ \text{Saving} = \text{R } 1.99 $$ Solly would save $\boxed{\text{R } 1.99}$ on transaction fees. Send me the next one 📸