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The opening balance is the amount of money available in the bank account at the beginning of the statement period, which is R9 872.50 on 01/02/2022.

Mathematics

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1.1.1
The opening balance is the amount of money available in the bank account at the beginning of the statement period, which is R9 872.50 on 01/02/2022.

1.1.2

  1. Identify the total amount debited for the cellphone account.

    From the statement, on 02/02/2022, "Debit order- cellphone account" is R289.32.

  2. Subtract the monthly contract fee from the total debit.

    Amount spent on calls=Total cellphone debit−Monthly contract fee\text{Amount spent on calls} = \text{Total cellphone debit} - \text{Monthly contract fee} Amount spent on calls=R 289.32−R 85.00\text{Amount spent on calls} = \text{R } 289.32 - \text{R } 85.00 Amount spent on calls=R 204.32\text{Amount spent on calls} = \text{R } 204.32

    Solly spent R 204.32\boxed{\text{R } 204.32} on calls in February.

    1.1.3

  3. Identify all ATM withdrawal amounts from the statement.

    On 06/02/2022, ATM Withdrawal = R1 000.00
    On 10/02/2022, ATM Withdrawal = R880.00

  4. Sum the ATM withdrawal amounts.

    Total ATM withdrawals=R 1000.00+R 880.00\text{Total ATM withdrawals} = \text{R } 1000.00 + \text{R } 880.00 Total ATM withdrawals=R 1880.00\text{Total ATM withdrawals} = \text{R } 1880.00

    The total amount Solly withdrew through ATM withdrawals is R 1880.00\boxed{\text{R } 1880.00}.

    1.1.4

  5. Locate the "Debit order - Car insurance" transaction.

    On 03/02/2022, "Debit order - Car insurance" is R1 000.00.
    Solly paid R 1000.00\boxed{\text{R } 1000.00} for Car Insurance.

    1.1.5

  6. Find the closing balance on the 21st of February.

    On 21/02/2022, after the "Cash deposit at Branch" and its "Transaction Fee", the closing balance is R2 227.96.
    The closing balance on the 21st of February is R 2227.96\boxed{\text{R } 2227.96}.

    1.1.6

  7. List all bank charges (Transaction Fees and Monthly account fee) from the statement.

    • 01/02/2022: Transaction Fee = R1.50
    • 02/02/2022: Transaction Fee = R6.00
    • 02/02/2022: Transaction Fee = R6.00
    • 03/02/2022: Transaction Fee = R6.00
    • 06/02/2022: Transaction Fee = R6.00
    • 10/02/2022: Transaction Fee = R6.00
    • 21/02/2022: Transaction Fee = R5.59
    • 28/02/2022: Monthly account fee = R8.20
  8. Sum all the bank charges.

    Total bank charges=1.50+6.00+6.00+6.00+6.00+6.00+5.59+8.20\text{Total bank charges} = 1.50 + 6.00 + 6.00 + 6.00 + 6.00 + 6.00 + 5.59 + 8.20 Total bank charges=R 47.29\text{Total bank charges} = \text{R } 47.29

    Solly's total bank charges for the month are R 47.29\boxed{\text{R } 47.29}.

    1.2.1

  9. Identify the fee structure for "Cash deposit (At the branch)" from Table 1.

    Fee = R2.50 + 0.95% of value.
    The deposit value is R325.00.

  10. Calculate the fee.

    Fee=R 2.50+(0.0095×R 325.00)\text{Fee} = \text{R } 2.50 + (0.0095 \times \text{R } 325.00) Fee=R 2.50+R 3.0875\text{Fee} = \text{R } 2.50 + \text{R } 3.0875 Fee=R 5.5875\text{Fee} = \text{R } 5.5875

    Rounding to two decimal places, the fee is R 5.59\boxed{\text{R } 5.59}.
    The statement shows R5.59, which matches the calculation.

    1.2.2

  11. Calculate the fee if the money was deposited at the ATM.

    From Table 1, "Cash deposit (At ATM)" fee = R0.90 per R100 (or part thereof).
    The deposit amount is R325.00.
    Number of R100 parts = ⌈325100⌉=⌈3.25⌉=4\lceil \frac{325}{100} \rceil = \lceil 3.25 \rceil = 4 parts.

    ATM deposit fee=4×R 0.90\text{ATM deposit fee} = 4 \times \text{R } 0.90 ATM deposit fee=R 3.60\text{ATM deposit fee} = \text{R } 3.60
  12. Calculate the saving.

    The fee at the branch was R5.59 (from 1.2.1).

    Saving=Branch deposit fee−ATM deposit fee\text{Saving} = \text{Branch deposit fee} - \text{ATM deposit fee} Saving=R 5.59−R 3.60\text{Saving} = \text{R } 5.59 - \text{R } 3.60 Saving=R 1.99\text{Saving} = \text{R } 1.99

    Solly would save R 1.99\boxed{\text{R } 1.99} on transaction fees.

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