What is the range of the data above?

To find the total number of students selected for height measurement, sum all the frequencies from the frequency table.
Total frequency = $3 + 5 + 8 + 2 + 9 + 7 + 8 + 6 + 2 + 4 + 3 = 57$.

• 57

To find how many students stand taller than 145 cm, sum the frequencies for heights greater than 145 cm. These heights are 146 cm, 147 cm, 148 cm, and 149 cm.
Frequencies for heights > 145 cm = $8 (\text{for } 146 \text{ cm}) + 6 (\text{for } 147 \text{ cm}) + 2 (\text{for } 148 \text{ cm}) + 4 (\text{for } 149 \text{ cm}) = 20$.

• 20

The data set is: 22, 20, 18, 23, 20, 26, 22, 20, 18, 20.
To find the range, identify the maximum and minimum values in the data set.
Maximum value = 26
Minimum value = 18
Range = Maximum value - Minimum value = $26 - 18 = 8$.

• 8

The data set is: 22, 20, 18, 23, 20, 26, 22, 20, 18, 20.
First, sort the data in ascending order: 18, 18, 20, 20, 20, 20, 22, 22, 23, 26.
The given table has class intervals 18-20 and 24-26. Assuming a consistent class width, the missing class interval would be 21-23.
Now, count the frequencies for each class from the sorted data:

• For the class 18-20 (values 18, 19, 20): The data points are 18, 18, 20, 20, 20, 20. Frequency = 6.
• For the class 21-23 (values 21, 22, 23): The data points are 22, 22, 23. Frequency = 3.
• For the class 24-26 (values 24, 25, 26): The data point is 26. Frequency = 1.

The completed table based on the provided data is:

$$\begin{array}{|c|c|} \hline \text{Number of Lollies in a jar} & \text{Frequency} \\ \hline 18-20 & 6 \\ \hline 21-23 & 3 \\ \hline 24-26 & 1 \\ \hline \end{array}$$

Note: The frequency for 24-26 derived from the data is 1, which differs from the '3' given in the original question's table. The answer above uses the frequencies calculated directly from the provided data set.