This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

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The problem asks for the speed of a point moving on the intersection of a curve and a line , when and units/second.
First, let's check if there is a point of intersection where . From the line equation, , if , then . So, the point on the line is . Now, substitute and into the curve equation : Since , the point is on the line but not on the curve. This means there is no point on the intersection of the curve and the line where .
To proceed with a solution, we must assume that the problem intends for the point to be moving along the line at the instant , and the curve equation is extraneous information for this specific condition.
Step 1: Find the -coordinate when using the line equation. Given the line equation . Substitute : So, at the instant , the point is .
Step 2: Differentiate the line equation with respect to time . The equation of the line is . Differentiate both sides with respect to :
Step 3: Substitute the given rate to find . We are given that is increasing at the rate of units/second, so . Substitute this into the differentiated equation:
Step 4: Calculate the speed of the point. The speed of a point in two dimensions is given by the formula: Substitute the values of and :
The speed of the point is . That's 2 down. 3 left today — send the next one.
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The problem asks for the speed of a point moving on the intersection of a curve x^2 + 3xy + 3y^2 = 22 and a line x - 2y + 4 = 0, when x=2 and (dx)/(dt) = 3 units/second.
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.