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The vertices of a triangle ABC are A (1,2),B(3,2), and C(3,5). (a) Plot triangle ABC on the Cartesian plane below. (Provide a grid for plotting)

Mathematics

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3 parts
b

1540 cm31540 \text{ cm}^3

c

440 cm2440 \text{ cm}^2

d

748 cm2748 \text{ cm}^2

Step-by-step solution

13 steps

Hapa kuna suluhisho la maswali yako:

28. (Inaendelea kutoka swali lililopita)
Ili kukokotoa ujazo na eneo la uso wa silinda, tunahitaji urefu wake. Kwa kuwa urefu haujatolewa katika swali, tutachukulia kuwa urefu (hh) wa silinda ni 10 cm10 \text{ cm} kwa madhumuni ya kuonyesha hesabu. Ikiwa urefu halisi ni tofauti, majibu yatabadilika ipasavyo.
Kutoka sehemu (a), tunajua rediasi (rr) = 7 cm7 \text{ cm} na eneo la msingi (AbaseA_{base}) = 154 cm2154 \text{ cm}^2. Pia, π=227\pi = \frac{22}{7}.

Part b· 3 steps

  1. Tumia formula ya ujazo wa silinda, V=πr2hV = \pi r^2 h.

    V=Abase×hV = A_{base} \times h
  2. Badilisha thamani za eneo la msingi na urefu uliochukuliwa.

    V=154 cm2×10 cmV = 154 \text{ cm}^2 \times 10 \text{ cm}
  3. Kokotoa ujazo.

    V=1540 cm3V = 1540 \text{ cm}^3

    Ujazo wa silinda ni 1540 cm3\boxed{1540 \text{ cm}^3}.

Part c

440 cm2440 \text{ cm}^2

  1. Tumia formula ya eneo la uso lililopinda la silinda, CSA=2πrhCSA = 2 \pi r h.

  2. Badilisha thamani za rediasi, π\pi, na urefu uliochukuliwa.

    CSA=2×227×7 cm×10 cmCSA = 2 \times \frac{22}{7} \times 7 \text{ cm} \times 10 \text{ cm}
  3. Rahisisha hesabu.

    CSA=2×22×10 cm2CSA = 2 \times 22 \times 10 \text{ cm}^2 CSA=440 cm2CSA = 440 \text{ cm}^2

    Eneo la uso lililopinda la silinda ni 440 cm2\boxed{440 \text{ cm}^2}.

Part d

748 cm2748 \text{ cm}^2

  1. Tumia formula ya jumla ya eneo la uso wa silinda iliyofungwa, TSA=2πrh+2πr2TSA = 2 \pi r h + 2 \pi r^2.

    Hii inaweza pia kuandikwa kama TSA=CSA+2×AbaseTSA = CSA + 2 \times A_{base}.

  2. Badilisha thamani za eneo la uso lililopinda na eneo la msingi.

    TSA=440 cm2+2×154 cm2TSA = 440 \text{ cm}^2 + 2 \times 154 \text{ cm}^2
  3. Kokotoa jumla ya eneo la uso.

    TSA=440 cm2+308 cm2TSA = 440 \text{ cm}^2 + 308 \text{ cm}^2 TSA=748 cm2TSA = 748 \text{ cm}^2

    Jumla ya eneo la uso wa silinda iliyofungwa ni 748 cm2\boxed{748 \text{ cm}^2}.

    29.

Part a· 4 steps

Ili kuchora pembetatu ABC kwenye ndege ya Cartesian, fuata hatua hizi:

  1. Panga nukta A(1,2).

    Anza kwenye asili (0,0), songa hatua 1 kulia kwenye mhimili wa x, kisha songa hatua 2 juu kwenye mhimili wa y. Weka alama hapo kama A.

  2. Panga nukta B(3,2).

    Anza kwenye asili (0,0), songa hatua 3 kulia kwenye mhimili wa x, kisha songa hatua 2 juu kwenye mhimili wa y. Weka alama hapo kama B.

  3. Panga nukta C(3,5).

    Anza kwenye asili (0,0), songa hatua 3 kulia kwenye mhimili wa x, kisha songa hatua 5 juu kwenye mhimili wa y. Weka alama hapo kama C.

  4. Unganisha nukta A na B kwa mstari, B na C kwa mstari, na C na A kwa mstari ili kuunda pembetatu ABC.

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