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Given the coordinates of triangle ABC as A(1, 1), B(3, 1), and C(1, 3), perform the following transformations: a) Plot triangle ABC. b) Translate ABC by vector [2, 2] to obtain A'B'C'. Find the coordi

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2 parts
b
(3, 3)
(5, 3)
(3, 5)
c
(-3, 3)
(-5, 3)
(-3, 5)

Step-by-step solution

4 steps

Nitaelewa kuwa "number 2,3,1" unamaanisha sehemu (a), (b), na (c) za swali namba 22.

Part 22

Kuratibu za pembetatu ABC ni A(1, 1), B(3, 1) na C(1, 3).

Part a

**Plot the triangle ABC.

Kuratibu za pembetatu ABC ni:
A = $(1, 1)$
B = $(3, 1)$
C = $(1, 3)$
Hizi ndizo pointi za kuchora pembetatu ABC.

Part b(3, 3)

**Triangle ABC undergoes a translation vector (22)\begin{pmatrix} 2 \\ 2 \end{pmatrix}. Obtain the image of A'B'C' under the transformation, write the coordinates of A'B'C'.

  1. Andika kuratibu za asili na vekta ya tafsiri.

    Kuratibu za asili: A(1,1)A(1, 1), B(3,1)B(3, 1), C(1,3)C(1, 3)
    Vekta ya tafsiri: T=(22)T = \begin{pmatrix} 2 \\ 2 \end{pmatrix}

  2. Tafsiri kila nukta kwa kuongeza vekta ya tafsiri.

    Kwa nukta A(x,y)A(x, y), picha yake A′(x′,y′)A'(x', y') inapatikana kwa x′=x+2x' = x + 2 na y′=y+2y' = y + 2.
    Kwa A(1, 1):
    A′=(1+2,1+2)=(3,3)A' = (1+2, 1+2) = (3, 3)

    Kwa B(3, 1):
    B′=(3+2,1+2)=(5,3)B' = (3+2, 1+2) = (5, 3)

    Kwa C(1, 3):
    C′=(1+2,3+2)=(3,5)C' = (1+2, 3+2) = (3, 5)

    Kuratibu za A'B'C' ni:
    A′=(3,3)A' = \boxed{(3, 3)}
    B′=(5,3)B' = \boxed{(5, 3)}
    C′=(3,5)C' = \boxed{(3, 5)}

Part c(-3, 3)

**A'B'C' undergoes a reflection along the line X=0, obtain the coordinates and plot on the graph points A''B''C'' under the transformation.

  1. Tambua mstari wa kuakisi.

    Mstari wa kuakisi ni X=0X=0, ambao ni mhimili wa y.

  2. Akisi kila nukta ya A'B'C' kwenye mhimili wa y.

    Kwa kuakisi kwenye mhimili wa y, kuratibu ya x hubadilisha ishara, na kuratibu ya y inabaki vile vile.
    Ikiwa nukta ni (x,y)(x, y), picha yake baada ya kuakisi kwenye X=0X=0 ni (−x,y)(-x, y).

    Kwa A'(3, 3):
    A′′=(−3,3)A'' = (-3, 3)

    Kwa B'(5, 3):
    B′′=(−5,3)B'' = (-5, 3)

    Kwa C'(3, 5):
    C′′=(−3,5)C'' = (-3, 5)

    Kuratibu za A''B''C'' ni:
    A′′=(−3,3)A'' = \boxed{(-3, 3)}
    B′′=(−5,3)B'' = \boxed{(-5, 3)}
    C′′=(−3,5)C'' = \boxed{(-3, 5)}

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