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What are the solutions to these math problems concerning divisibility, number properties, and basic arithmetic?
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a) The number 2,135 is divisible by 5. b) Reason: A number is divisible by 5 if its last digit is 0 or 5. The last digit of 2,135 is 5.
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Step 1: Identify the greatest 8-digit number. The greatest 8-digit number is 99,999,999.
Identify the smallest 9-digit number.
The smallest 9-digit number is 100,000,000.Calculate the difference.
$$ 100,000,000 - 99,999,999 = 1 $$ The difference is $\boxed{1}$.3. Given and .
Substitute the values of and into the expression.
$$ (a+b) \times 6 = (6+1) \times 6 $$Perform the addition inside the parentheses.
$$ 7 \times 6 $$Perform the multiplication.
$$ 42 $$ The value is $\boxed{42}$.4. a) Seven hundred and forty-five million, two hundred and three thousand, six hundred and twelve is written as . b) Eighty-nine million, four thousand and seventy is written as .
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a) 508,076,314 is written as Five hundred eight million, seventy-six thousand, three hundred fourteen. b) 300,000,009 is written as Three hundred million, nine.
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a) In 927,534,218, the digit 7 is in the millions place. Its total value is . b) In 240,815,963, the digit 4 is in the ten millions place. Its total value is .
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a) Round 489,736,214 to the nearest hundred million. The hundred millions digit is 4. The digit to its right is 8. Since , we round up the 4. The rounded number is . b) Round 72,361,983 to the nearest ten million. The ten millions digit is 7. The digit to its right is 2. Since , we keep the 7 as it is. The rounded number is .
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a) The sequence is 2, 6, 18, .... The common ratio is and . The next three numbers are: The next three numbers are . b) The sequence is 105, 95, 85, .... The common difference is and . The next three numbers are: The next three numbers are .
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The numbers are 308,419,621 and 381,429,216. Comparing the numbers, we look at the digits from left to right. The first digit (hundred millions place) is 3 for both. The second digit (ten millions place) is 0 for the first number and 8 for the second. Since , the first number is smaller. Arranged in increasing order: .
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a) Test 3456 by 2. A number is divisible by 2 if its last digit is an even number. The last digit of 3456 is 6, which is an even number. Therefore, 3456 is divisible by 2. b) Test 936 by 11. A number is divisible by 11 if the alternating sum of its digits is divisible by 11. For 936: . Since 12 is not divisible by 11, 936 is not divisible by 11.
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a) Express 84 as a product of prime factors.
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Divide 84 by the smallest prime number, 2.
$$ 84 = 2 \times 42 $$Divide 42 by 2.
$$ 42 = 2 \times 21 $$Divide 21 by the next smallest prime number, 3.
$$ 21 = 3 \times 7 $$Combine the prime factors.
$$ 84 = 2 \times 2 \times 3 \times 7 = \boxed{2^2 \times 3 \times 7} $$
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