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This is a set of math problems involving addition, subtraction, and properties of arithmetic. Some questions require matching, others involve calculations or filling in blanks.

Mathematics

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c)

  1. Add the distances travelled by train, bus, and car.

    1,632 km+324 km+86 km=2,042 km1,632 \text{ km} + 324 \text{ km} + 86 \text{ km} = 2,042 \text{ km}

    The total distance travelled is 2,042 km.

    The correct option is i).

    i) 2,042 km\boxed{\text{i) } 2,042 \text{ km}}

    d)

  2. Perform the addition.

    8,396+14,327=22,7238,396 + 14,327 = 22,723

  3. Perform the subtraction.

    22,723−12,846=9,87722,723 - 12,846 = 9,877

    The result is 9,877.

    The correct option is iv).

    iv) 9,877\boxed{\text{iv) } 9,877}

    Match the following.

    a)

  4. Subtract the numbers.

    53,896−25,603=28,29353,896 - 25,603 = 28,293

    Matches v).

    b)

  5. Subtract the numbers.

    96,531−76,320=20,21196,531 - 76,320 = 20,211

    Matches i).

    c)

  6. Subtract the numbers.

    69,590−43,299=26,29169,590 - 43,299 = 26,291

    Matches ii).

    d)

  7. Subtract the numbers.

    87,965−46,003=41,96287,965 - 46,003 = 41,962

    Matches iii).

    e)

  8. Subtract the numbers.

    70,707−60,616=10,09170,707 - 60,616 = 10,091

    Matches iv).

    Fill in the blanks.

    a)

  9. Use the commutative property of addition (a+b=b+aa+b = b+a).

    5,692+202=202+5,6925,692 + 202 = 202 + 5,692

  10. Perform the addition.

    5,692+202=5,8945,692 + 202 = 5,894 5,692,5,894\boxed{5,692, 5,894}

    b)

  11. Use the commutative property of addition (a+b=b+aa+b = b+a).

    2,385+123=123+2,3852,385 + 123 = 123 + 2,385 2,385\boxed{2,385}

    c)

  12. Use the additive identity property (a+0=aa+0 = a).

    7,831+0=7,8317,831 + 0 = 7,831 7,831\boxed{7,831}

    d)

  13. Let the blank be xx.

    x+8,998=8,999x + 8,998 = 8,999

  14. Solve for xx.

    x=8,999−8,998x = 8,999 - 8,998 x=1x = 1 1\boxed{1}

    e)

  15. Let the blank be xx.

    3,476=x−13,476 = x - 1

  16. Solve for xx.

    x=3,476+1x = 3,476 + 1 x=3,477x = 3,477 3,477\boxed{3,477}

    Find the missing digits.

    a)

  17. Determine the missing digits by subtracting the bottom number from the top number to get the result.

    Th H T O
    8 6 3 9

    • 1 5 5 5

      7 0 8 4 The missing digits are 1,5,5,51, 5, 5, 5.
    1555\boxed{1555}

    b)

  18. Determine the missing digits by adding the bottom number to the result to get the top number.

    Th H T O
    9 2 8 0

    • 3 4 5 6

      5 8 2 4 The missing digits are 9,2,8,09, 2, 8, 0.
    9280\boxed{9280}

    c)

  19. Determine the missing digits by performing the addition.

    Th H T O
    5 9 6 6

    • 1 3 3 5

      7 3 0 1 The missing digits are 7,07, 0.
    7,0\boxed{7, 0}

    5. Solve the following word problems.

    a)

  20. Identify the cost price and selling price.

    Cost Price = ₹ 50,840
    Selling Price = ₹ 94,000

  21. Calculate the profit (how much richer he was).

    Profit = Selling Price - Cost Price

    94,000−50,840=43,16094,000 - 50,840 = 43,160

    The man was richer by ₹ 43,160.

    ₹ 43,160\boxed{\text{₹ } 43,160}

    b)

  22. Find the marks Neena secured in the second term.

    Marks in first term = 350
    Marks in second term = Marks in first term - 73

    350−73=277350 - 73 = 277

    Neena secured 277 marks in the second term.

  23. Find the total marks secured in both terms.

    Total marks = Marks in first term + Marks in second term

    350+277=627350 + 277 = 627

    Neena secured 627 marks in both terms.

    Second term: 277 marks, Both terms: 627 marks\boxed{\text{Second term: } 277 \text{ marks, Both terms: } 627 \text{ marks}}
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