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What is the square root of 1849?

Mathematics

ScanSolve AI Answer

Answer

1849=43\sqrt{1849} = 43

Step-by-step solution

6 steps
  1. Pair the digits of the number 1849 from the right.

    The pairs are $(18)$ and $(49)$.

  2. Find the largest whole number whose square is less than or equal to the first pair, 18.

    42=164^2 = 16
    52=255^2 = 25
    Since 16<1816 < 18 and 25>1825 > 18, the number is 4. Write 4 as the first digit of the square root.

  3. Subtract 42=164^2 = 16 from 18.

    18−16=218 - 16 = 2
  4. Bring down the next pair of digits, 49, next to the remainder.

    The new number is 249.

  5. Double the current quotient (4×2=84 \times 2 = 8).

    Write this as the new divisor's first digit.
    Now, we need to find a digit 'x' such that when 'x' is placed next to 8 (forming 8x8x) and multiplied by 'x', the product is less than or equal to 249.
    Let's try x=3x=3:

    83×3=24983 \times 3 = 249
  6. Write 3 as the next digit in the square root.

    Subtract 249 from 249.

    249−249=0249 - 249 = 0

    Since the remainder is 0 and there are no more pairs to bring down, the square root is 43.

    Therefore, the positive square root of 1849 is:

    1849=43\sqrt{1849} = \boxed{43}
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