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The sum of the first four terms in the expansion of (1-2x)4 is equal to the sum of the first three terms in the expansion of (1-x)8. Show that this is true only if x=0 or x=- rac14.

Mathematics

ScanSolve AI Answer

9. The sum of the first four terms in the expansion of (1−2x)4(1-2x)^4 is equal to the sum of the first three terms in the expansion of (1−x)8(1-x)^8. Show that this is true only if x=0x=0 or x=−14x=-\frac{1}{4}.

Step 1: Find the sum of the first four terms of (1−2x)4(1-2x)^4.
Using the binomial expansion (a+b)n=∑k=0n(nk)an−kbk(a+b)^n = \sum_{k=0}^n \binom{n}{k} a^{n-k} b^k, with a=1a=1, b=−2xb=-2x, and n=4n=4:
The first four terms are for $k=0, 1, 2,

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