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The sum of the interior angles of a polygon is 1980^ exto. Find the number of sides the polygon has. 11. The diagram below is a sketch of a rice field (not drawn to scale), use it to generate a survey

Mathematics

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10. The sum of the interior angles of a polygon is 1980∘1980^\circ. Find the number of sides the polygon has.

  1. Use the formula for the sum of interior angles of a polygon.

    The sum of the interior angles SS of a polygon with nn sides is given by the formula:

    S=(n−2)×180∘S = (n-2) \times 180^\circ
  2. Substitute the given sum into the formula.

    We are given S=1980∘S = 1980^\circ:

    1980∘=(n−2)×180∘1980^\circ = (n-2) \times 180^\circ
  3. Solve for nn.

    Divide both sides by 180∘180^\circ:

    1980180=n−2\frac{1980}{180} = n-2 11=n−211 = n-2

    Add 2 to both sides:

    n=11+2n = 11 + 2 n=13n = 13

    The polygon has 13 sides\boxed{13 \text{ sides}}.

    11. The diagram below is a sketch of a rice field (not drawn to scale), use it to generate a surveyor's field book. (All measurements are in metres)

    A surveyor's field book records measurements taken along a baseline. The readings are typically recorded from the bottom of the page upwards, representing movement along the baseline from the starting point (X) to the end point (Y).

  4. Identify the baseline and its total length.

    The baseline is XY, and its total length is 150 m.

  5. Extract the chainage (distance along the baseline from X) and offset measurements from the diagram.

    • From X (0m): Starting point.
    • At 30m from X: Left offset to F is 20m. Right offset to A is 20m.
    • At 60m from X: Left offset to E is 50m.
    • At 100m from X: Right offset to B is 40m.
    • At 120m from X: Left offset to D is 45m. Right offset to C is 40m.
    • To Y (150m): End point of the baseline.
  6. Construct the field book.

    Left OffsetChainage (m)Right Offset
    150
    45 to D12040 to C
    10040 to B
    50 to E60
    20 to F3020 to A
    0
    TO Y
    FROM X

    12. A boy walk directly from point Q towards the foot of a vertical flag post 200m away. After conveying a distance of 140m, he observes the angle of elevation of the top of the flag post is 75∘75^\circ.

  7. Determine the boy's new distance from the flag post.

    Initial distance from Q to the foot of the flag post = 200 m.
    Distance walked by the boy towards the flag post = 140 m.
    New distance from the boy to the foot of the flag post = 200 m−140 m=60 m200 \text{ m} - 140 \text{ m} = 60 \text{ m}.

  8. Form a right-angled triangle.

    Let hh be the height of the flag post.
    The distance from the boy's new position to the foot of the flag post is 60 m.
    The angle of elevation to the top of the flag post is 75∘75^\circ.
    This forms a right-angled triangle where:

    • The height of the flag post (hh) is the opposite side to the angle of elevation.
    • The distance from the boy to the foot of the flag post (60 m) is the adjacent side to the angle of elevation.
  9. Use the tangent trigonometric ratio.

    The tangent of an angle in a right-angled triangle is the ratio of the opposite side to the adjacent side:

    tan⁡(θ)=OppositeAdjacent\tan(\theta) = \frac{\text{Opposite}}{\text{Adjacent}} tan⁡(75∘)=h60\tan(75^\circ) = \frac{h}{60}
  10. Solve for hh.

    h=60×tan⁡(75∘)h = 60 \times \tan(75^\circ)

    Using a calculator, tan⁡(75∘)≈3.73205\tan(75^\circ) \approx 3.73205

    h=60×3.73205h = 60 \times 3.73205 h=223.923h = 223.923

    Rounding to two decimal places:

    h≈223.92 mh \approx 223.92 \text{ m}

    The height of the flag post is approximately 223.92 m\boxed{223.92 \text{ m}}.

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