A polygon has a sum of interior angles equal to 1980 degrees. How many triangles can it be subdivided into, and how many sides does it have?

The sum of the interior angles of a polygon with $n$ sides is given by $S = (n-2) \times 180^\circ$. The term $(n-2)$ represents the number of non-overlapping triangles the polygon can be divided into.

Given that the sum of the interior angles is $1980^\circ$. Let $T$ be the number of triangles.

The number of triangles the polygon can be subdivided into is 11.

b) The number of sides the polygon has.

The number of triangles a polygon can be subdivided into is $n-2$, where $n$ is the number of sides.

The number of sides the polygon has is 13.

The final answers are:

a) The number of triangles the polygon can be subdivided into is $\boxed{11}$.

b) The number of sides the polygon has is $\boxed{13}$.