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The table below shows the mark scored by students in a maths exam. Draw a cumulative frequency curve and use your graph to find: (i) The median (ii) The quartile deviation (iii) The number of students who scored above 67.

Mathematics

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Answers

3 parts
a(i)

56.9 marks56.9 \text{ marks}

a(ii)
7.85
a(iii)

16 wanafunzi16 \text{ wanafunzi}

Step-by-step solution

9 steps

Haya Terry, twendelee na swali hili la Hisabati.

Jedwali linaonyesha alama zilizopatikana na wanafunzi katika mtihani wa Hisabati.

Part a· 2 steps

Chora curve ya masafa jumla (cumulative frequency curve) na utumie grafu yako kupata

  1. Unda jedwali la masafa jumla (cumulative frequency table).

    Kwanza, tunahitaji mipaka ya juu ya darasa (upper class boundaries) na masafa jumla (cumulative frequency).

    ClassUpper Class BoundaryFrequency (f)Cumulative Frequency (cf)
    20 - 2929.500
    30 - 3939.533
    40 - 4949.51720
    50 - 5959.52747
    60 - 6969.52370
    70 - 7979.5878
    80 - 8989.5280

    Jumla ya wanafunzi (NN) ni 80.

  2. Chora curve ya masafa jumla (ogive).

    • Kwenye x-axis, chora alama (marks) kwa kutumia mipaka ya juu ya darasa (upper class boundaries).
    • Kwenye y-axis, chora masafa jumla (cumulative frequency).
    • Panga pointi zifuatazo: $(29.5, 0), (39.5, 3), (49.5, 20), (59.5, 47), (69.5, 70), (79.5, 78), (89.5, 80)$.
    • Unganisha pointi hizi kwa kutumia mstari laini (smooth curve).

    (Kumbuka: Kwa kuwa siwezi kuchora grafu moja kwa moja hapa, maelezo hapo juu yanaeleza jinsi mchoro unavyopaswa kuonekana. Majibu yafuatayo yanatokana na usomaji wa kawaida wa grafu kama hiyo.)

Part a(i)

56.9 marks56.9 \text{ marks}

Median

  1. Tafuta nafasi ya median.

    Nafasi ya median ni N2=802=40\frac{N}{2} = \frac{80}{2} = 40.

  2. Soma median kutoka kwenye grafu.

    Kutoka kwenye y-axis, tafuta 40. Chora mstari mlalo kuelekea curve, kisha chora mstari wima kushuka kwenye x-axis.
    Thamani ya x-axis itakuwa median.
    Kutokana na grafu iliyochorwa vizuri, median inapaswa kuwa karibu na 56.9 marks\boxed{56.9 \text{ marks}}.

Part a(ii)7.85

Quartile deviation

  1. Tafuta nafasi za quartiles za kwanza na ya tatu.

    Nafasi ya Quartile ya Kwanza (Q1Q_1) ni N4=804=20\frac{N}{4} = \frac{80}{4} = 20.
    Nafasi ya Quartile ya Tatu (Q3Q_3) ni 3N4=3×804=60\frac{3N}{4} = \frac{3 \times 80}{4} = 60.

  2. Soma Q1Q_1 na Q3Q_3 kutoka kwenye grafu.

    • Kwa Q1Q_1: Kutoka kwenye y-axis, tafuta 20. Chora mstari mlalo kuelekea curve, kisha chora mstari wima kushuka kwenye x-axis. Q1Q_1 inapaswa kuwa karibu na 49.5 marks49.5 \text{ marks}.
    • Kwa Q3Q_3: Kutoka kwenye y-axis, tafuta 60. Chora mstari mlalo kuelekea curve, kisha chora mstari wima kushuka kwenye x-axis. Q3Q_3 inapaswa kuwa karibu na 65.2 marks65.2 \text{ marks}.
  3. Kokotoa quartile deviation.

    Quartile Deviation (QD) =Q3−Q12= \frac{Q_3 - Q_1}{2}

    QD=65.2−49.52\text{QD} = \frac{65.2 - 49.5}{2} QD=15.72\text{QD} = \frac{15.7}{2} QD=7.85\text{QD} = 7.85

    Quartile deviation ni 7.85\boxed{7.85}.

Part a(iii)

16 wanafunzi16 \text{ wanafunzi}

Idadi ya wanafunzi waliofunga zaidi ya 67.

  1. Tafuta masafa jumla kwa alama 67.

    Kutoka kwenye x-axis, tafuta 67. Chora mstari wima kuelekea curve, kisha chora mstari mlalo kuelekea y-axis.
    Masafa jumla kwa alama 67 (cf67cf_{67}) inapaswa kuwa karibu na 64 wanafunzi.

  2. Kokotoa idadi ya wanafunzi waliofunga zaidi ya 67.

    Idadi ya wanafunzi waliofunga zaidi ya 67 = Jumla ya wanafunzi - cf67cf_{67}

    Idadi=80−64\text{Idadi} = 80 - 64 Idadi=16 wanafunzi\text{Idadi} = 16 \text{ wanafunzi}

    Idadi ya wanafunzi waliofunga zaidi ya 67 ni 16 wanafunzi\boxed{16 \text{ wanafunzi}}.

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