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The table shows the marks obtained by pupils and the corresponding number of pupils for each mark. We will interpret the column "Percentage Number of pupils" as "Number of pupils" because the sum of t

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3 parts
a

34\text{34}

b

517\frac{5}{17}

c

534\frac{5}{34}

Step-by-step solution

8 steps

Here is the solution based on the provided image.

The table shows the marks obtained by pupils and the corresponding number of pupils for each mark. We will interpret the column "Percentage Number of pupils" as "Number of pupils" because the sum of these values (34) does not equal 100, which would be expected if they were percentages of the total class.

The table is:

MARKS INNumber of pupils11111010114488\begin{array}{|c|c|} \hline \text{MARKS IN} & \text{Number of pupils} \\ \hline 11 & 11 \\ 10 & 10 \\ 1 & 1 \\ 4 & 4 \\ 8 & 8 \\ \hline \end{array}

Part a· 1 step

How many people are in the class?

  1. Sum the number of pupils from the table.

    Total number of pupils=11+10+1+4+8\text{Total number of pupils} = 11 + 10 + 1 + 4 + 8 Total number of pupils=34\text{Total number of pupils} = 34

    The total number of people in the class is 34\boxed{\text{34}}.

Part b

517\frac{5}{17}

What is the probability of a pupil who scored 10 marks?

  1. Identify the number of pupils who scored 10 marks.

    From the table, the number of pupils who scored 10 marks is 10.

  2. Calculate the probability.

    The probability is given by the ratio of the number of favorable outcomes to the total number of outcomes.

    P(scored 10 marks)=Number of pupils who scored 10 marksTotal number of pupilsP(\text{scored 10 marks}) = \frac{\text{Number of pupils who scored 10 marks}}{\text{Total number of pupils}} P(scored 10 marks)=1034P(\text{scored 10 marks}) = \frac{10}{34}

  3. Simplify the fraction.

    P(scored 10 marks)=517P(\text{scored 10 marks}) = \frac{5}{17}

    The probability of a pupil scoring 10 marks is 517\boxed{\frac{5}{17}}.

Part c

534\frac{5}{34}

What is the probability that a pupil chosen at random from the class scored... (The question is incomplete in the image.)

Assumption: We will assume the question asks for the probability that a pupil chosen at random from the class scored less than 8 marks.

  1. Identify the marks that are less than 8.

    From the table, the marks less than 8 are 1 and 4.

  2. Identify the number of pupils for these marks.

    Number of pupils who scored 1 mark = 1.
    Number of pupils who scored 4 marks = 4.

  3. Calculate the total number of pupils who scored less than 8 marks.

    Number of pupils (less than 8 marks)=1+4=5\text{Number of pupils (less than 8 marks)} = 1 + 4 = 5

  4. Calculate the probability.

    P(scored less than 8 marks)=Number of pupils who scored less than 8 marksTotal number of pupilsP(\text{scored less than 8 marks}) = \frac{\text{Number of pupils who scored less than 8 marks}}{\text{Total number of pupils}} P(scored less than 8 marks)=534P(\text{scored less than 8 marks}) = \frac{5}{34}

    The probability that a pupil chosen at random scored less than 8 marks is 534\boxed{\frac{5}{34}}.

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