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What is the value of a such that the equation (3a+1)x2 + (a+2)x + 1 = 0 shall have equal roots.

Mathematics

ScanSolve AI Answer

To solve these problems, we use the concept of the discriminant of a quadratic equation Ax2+Bx+C=0Ax^2 + Bx + C = 0. The discriminant is given by Δ=B2−4AC\Delta = B^2 - 4AC.

  • For equal roots, Δ=0\Delta = 0.
  • For real roots, Δ≥0\Delta \ge 0.

1. What is the value of aa such that the equation (3a+1)x2+(a+2)x+1=0(3a+1)x^2 + (a+2)x + 1 = 0 shall have equal roots.

Step 1: Identify the coefficients A, B, and C from the given quadratic equation.
The equation is $(3a+1)x^2 + (a+2)x +

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