The weights (in kg) of 20 boys in a class are given. Prepare a frequency distribution table and find the range of the data.

Here are the solutions to questions 48 to 50. 48. Weights (in kg) of 20 boys in a class are given below: The given data is: 48, 46, 50, 44, 50, 48, 44, 50, 42, 48 42, 46, 40, 44, 46, 48, 50, 42, 46, 44 Prepare a frequency distribution table for the above data. Step 1: List the unique weights in ascending order. The unique weights are 40, 42, 44, 46, 48, 50. Step 2: Count the frequency of each weight. 40 kg: 1 42 kg: 3 44 kg: 5 46 kg: 4 48 kg: 4 50 kg: 3 Total count: 1+3+5+4+4+3 = 20, which matches the number of boys. Here is the frequency distribution table: | Weight (in kg) | Frequency | | :------------- | :-------- | | 40 | 1 | | 42 | 3 | | 44 | 5 | | 46 | 4 | | 48 | 4 | | 50 | 3 | | Total | 20 | What is the range of the data? Step 1: Identify the maximum and minimum values in the data. Maximum weight = 50 kg Minimum weight = 40 kg Step 2: Calculate the range. Range = Maximum value - Minimum value Range = 50 kg - 40 kg = 10 kg The range of the data is 10 kg. 49. During a rainy season, students of a class made a count of the umbrellas, which students brought to the class on Monday, Tuesday, Wednesday, Thursday, Friday and Saturday. The count was as under: Monday: 25 Tuesday: 20 Wednesday: 10 Thursday: 20 Friday: 15 Saturday: 30 Represent this information through a pictograph. Step 1: Choose a suitable symbol and scale. The numbers are 25, 20, 10, 20, 15, 30. All are multiples of 5. Let's use the symbol ☂️ to represent 5 umbrellas. Scale: ☂️ = 5 umbrellas Step 2: Convert the counts into symbols. Monday: 25 ÷ 5 = 5 umbrellas ☂️☂️☂️☂️☂️ Tuesday: 20 ÷ 5 = 4 umbrellas ☂️☂️☂️☂️ Wednesday: 10 ÷ 5 = 2 umbrellas ☂️☂️ Thursday: 20 ÷ 5 = 4 umbrellas ☂️☂️☂️☂️ Friday: 15 ÷ 5 = 3 umbrellas ☂️☂️☂️ Saturday: 30 ÷ 5 = 6 umbrellas ☂️☂️☂️☂️☂️☂️ Here is the pictograph: | Day | Number of Umbrellas | | :-------- | :------------------ | | Monday | ☂️☂️☂️☂️☂️ | | Tuesday | ☂️☂️☂️☂️ | | Wednesday | ☂️☂️ | | Thursday | ☂️☂️☂️☂️ | | Friday | ☂️☂️☂️ | | Saturday | ☂️☂️☂️☂️☂️☂️ | Scale: ☂️ = 5 umbrellas 50. The following are the details of number of students present in a class of 30 during a week. Represent it by a pictograph. | Days | Number of students present | | :-------- | :------------------------- | | Monday | 24 | | Tuesday | 26 | | Wednesday | 28 | | Thursday | 30 | | Friday | 29 | | Saturday | 22 | Represent it by a pictograph. Step 1: Choose a suitable symbol and scale. The numbers are 24, 26, 28, 30, 29, 22. These numbers include odd and even values. Let's use the symbol 🧍 to represent 2 students. For odd numbers, we will use a half symbol. Scale: 🧍 = 2 students, and 🚹 = 1 student (half symbol) Step 2: Convert the counts into symbols. Monday: 24 ÷ 2 = 12 students 🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍 Tuesday: 26 ÷ 2 = 13 students 🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍 Wednesday: 28 ÷ 2 = 14 students 🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍 Thursday: 30 ÷ 2 = 15 students 🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍 Friday: 29 = 14 × 2 + 1. So, 14 full symbols and 1 half symbol 🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🚹 Saturday: 22 ÷ 2 = 11 students 🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍 Here is the pictograph: | Day | Number of Students Present | | :-------- | :------------------------- | | Monday | 🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍 | | Tuesday | 🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍 | | Wednesday | 🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍 | | Thursday | 🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍 | | Friday | 🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🚹 | | Saturday | 🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍🧍 | Scale: 🧍 = 2 students, 🚹 = 1 student Last free one today — make it count tomorrow, or type /upgrade for unlimited.