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Given the following baby weights (in kg), construct a grouped frequency distribution and determine the class width: [list of weights]

Mathematics

ScanSolve AI Answer

Answer

1.00\text{1.00}

4.505\text{4.505}

4.01 and 5.00\text{4.01 and 5.00}

Step-by-step solution

3 steps
  1. Classify the data into a grouped frequency distribution.

    First, list the given baby weights:
    2.57, 4.21, 1.05, 3.06, 4.50, 5.05, 3.45, 0.92
    3.12, 2.87, 0.76, 4.18, 5.93, 4.18, 2.03, 0.57, 1.85
    4.16, 3.41, 1.86, 2.53, 1.48, 3.85, 5.12, 3.24, 1.89
    2.51, 0.93, 1.24, 3.21, 5.86, 3.57, 2.18, 4.29, 3.30
    0.91, 0.82, 1.47, 4.25, 3.81, 2.48, 1.27, 5.35, 3.33

    The classes are: 0.01 – 1.00, 1.01 – 2.00, 2.01 – 3.00, 3.01 – 4.00, 4.01 – 5.00, 5.01 – 6.00.

    Now, count the frequency for each class:

    • Class 0.01 – 1.00: 0.92, 0.76, 0.57, 0.93, 0.91, 0.82 (Frequency = 6)
    • Class 1.01 – 2.00: 1.05, 1.85, 1.86, 1.48, 1.89, 1.24, 1.47, 1.27 (Frequency = 8)
    • Class 2.01 – 3.00: 2.57, 2.87, 2.03, 2.53, 2.51, 2.18, 2.48 (Frequency = 7)
    • Class 3.01 – 4.00: 3.06, 3.45, 3.12, 3.41, 3.85, 3.24, 3.21, 3.57, 3.30, 3.81, 3.33 (Frequency = 11)
    • Class 4.01 – 5.00: 4.21, 4.50, 4.18, 4.18, 4.16, 4.29, 4.25 (Frequency = 7)
    • Class 5.01 – 6.00: 5.05, 5.93, 5.12, 5.86, 5.35 (Frequency = 5)

    The grouped frequency distribution is:

    Class (Weight in kg)Frequency0.01−1.0061.01−2.0082.01−3.0073.01−4.00114.01−5.0075.01−6.005Total44\begin{array}{|c|c|} \hline \textbf{Class (Weight in kg)} & \textbf{Frequency} \\ \hline 0.01 - 1.00 & 6 \\ 1.01 - 2.00 & 8 \\ 2.01 - 3.00 & 7 \\ 3.01 - 4.00 & 11 \\ 4.01 - 5.00 & 7 \\ 5.01 - 6.00 & 5 \\ \hline \textbf{Total} & \textbf{44} \\ \hline \end{array}
  2. Find the class width.

    The class width is the difference between consecutive lower class limits (or upper class limits).
    Using the first two classes:
    Lower limit of the second class = 1.01
    Lower limit of the first class = 0.01
    Class width = 1.01−0.01=1.001.01 - 0.01 = 1.00

    Alternatively, using class boundaries:
    For the class 0.01 – 1.00, the lower class boundary is 0.01−0.005=0.0050.01 - 0.005 = 0.005 and the upper class boundary is 1.00+0.005=1.0051.00 + 0.005 = 1.005.
    Class width = 1.005−0.005=1.001.005 - 0.005 = 1.00.

    The class width is 1.00\boxed{\text{1.00}}.

  3. For the class 4.01 – 5.00, name the value of

    • The class center
    • The class limit
    • The class center (or midpoint) is the average of the lower and upper class limits.

      Class Center=Lower Class Limit+Upper Class Limit2\text{Class Center} = \frac{\text{Lower Class Limit} + \text{Upper Class Limit}}{2}

      For the class 4.01 – 5.00:

      Class Center=4.01+5.002=9.012=4.505\text{Class Center} = \frac{4.01 + 5.00}{2} = \frac{9.01}{2} = 4.505

      The class center is 4.505\boxed{\text{4.505}}.

    • The class limits are the smallest and largest values that can belong to the class. For the class 4.01 – 5.00, the class limits are 4.01 and 5.00. The class limits are 4.01 and 5.00\boxed{\text{4.01 and 5.00}}.

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