Table 2.1 gives the weights (in kg) of 35 students in a particular school. Construct a cumulative frequency table for the distribution. Draw a cumulative frequency curve for the distribution. Use your curve to estimate the median.

The class intervals are given as 40-44, 45-49, etc. To make them continuous for a cumulative frequency curve, we use upper class boundaries. For example, for 40-44, the upper boundary is 44.5 (midpoint between 44 and 45).

The cumulative frequency table is as follows:

The points to plot are:
$(44.5, 5)$
$(49.5, 11)$
$(54.5, 21)$
$(59.5, 25)$
$(64.5, 30)$
$(69.5, 33)$
$(74.5, 35)$
It is also good practice to start the curve from the lower boundary of the first class with a cumulative frequency of 0. The lower boundary for 40-44 is 39.5, so plot $(39.5, 0)$.

(As an AI, I cannot draw the curve, but the description above outlines how to construct it.)

The total number of students ($N$) is 35. The median is the value at the $\frac{N}{2}$-th position.

Draw a horizontal line from 17.5 on the y-axis to intersect the cumulative frequency curve.

Read the value on the x-axis. This value is the estimated median.

Based on the cumulative frequency table, the 17.5th value falls within the 50-54 kg class (where cumulative frequency goes from 11 to 21).
Using interpolation for a precise estimate (which would be read from a well-drawn curve):
Lower boundary of median class ($L$) = 49.5
Cumulative frequency before median class ($CF$) = 11
Frequency of median class ($f$) = 10
Class width ($c$) = 5

(Your graphical estimate from the curve should be close to this value.)