Without using a calculator, evaluate (-13+5-70 / 5)/(9-14 x -3 + 21). Simplify the expression 3a3b-32-1a⁻²b2. A triangle ABC is such that AB = 11 cm, BC = 8 cm and ABC = 56^. Calculate the length of AC to 2 decimal places.

Kwa nambari: $-13+5-70 \div 5$
Kwanza fanya mgawanyiko: $70 \div 5 = 14$.
Kisha fanya kujumlisha na kutoa kutoka kushoto kwenda kulia:
$-13 + 5 = -8$
$-8 - 14 = -22$

Kwa denominata: $9-14 \times -3+21$
Kwanza fanya kuzidisha: $14 \times -3 = -42$.
Kisha fanya kujumlisha na kutoa kutoka kushoto kwenda kulia:
$9 - (-42) + 21 = 9 + 42 + 21$
$9 + 42 = 51$
$51 + 21 = 72$

$$\frac{-22}{72} = \frac{-11}{36}$$

Jibu la mwisho ni:

$$\boxed{-\frac{11}{36}}$$

$$6 \times a^5 \times \frac{1}{b^5} = \frac{6a^5}{b^5}$$

Jibu la mwisho ni:

$$\boxed{\frac{6a^5}{b^5}}$$