A triangle ABC is such that AB = 11 cm, BC = 8 cm and ABC = 53°. Calculate the area of the triangle correct to 2 decimal places.

Fomula ni $A = \frac{1}{2}ab \sin C$, ambapo $a$ na $b$ ni urefu wa pande na $C$ ni pembe iliyopo katikati ya pande hizo.
Katika kesi hii, $a = AB = 11 \text{ cm}$, $b = BC = 8 \text{ cm}$, na $C = \angle ABC = 53^\circ$.

$$A = \frac{1}{2} \times AB \times BC \times \sin(\angle ABC)$$

$$A = \frac{1}{2} \times 11 \times 8 \times 0.7986355$$ $$A = 44 \times 0.7986355$$ $$A = 35.1400 \text{ cm}^2$$

$$A \approx 35.14 \text{ cm}^2$$

Eneo la pembetatu ni 35.14 cm².

$$35.14 \text{ cm}^2$$