Given the following list of weights, calculate the mean, median, and mode. Weights: [125, 141, 141, 132, 155, 160, 185, 165, 172, 148, 131, 154, 162, 148, 135, 181, 172, 133, 141, 135]

The mean is the sum of all values divided by the number of values.

$$\text{Sum} = 125 + 141 + 141 + 132 + 155 + 160 + 185 + 165 + 172 + 148 + 131 + 154 + 162 + 148 + 135 + 181 + 172 + 133 + 141 + 135$$ $$\text{Sum} = 2986$$ $$\text{Mean} = \frac{\text{Sum}}{n} = \frac{2986}{20} = 149.3$$

First, arrange the weights in ascending order:
$125, 131, 132, 133, 135, 135, 141, 141, 141, 148, 148, 154, 155, 160, 162, 165, 172, 172, 181, 185$
Since there are 20 values (an even number), the median is the average of the two middle values, which are the $10^{\text{th}}$ and $11^{\text{th}}$ values.
The $10^{\text{th}}$ value is 148.
The $11^{\text{th}}$ value is 148.

$$\text{Median} = \frac{10^{\text{th}} \text{ value} + 11^{\text{th}} \text{ value}}{2} = \frac{148 + 148}{2} = \frac{296}{2} = 148$$

The mode is the value that appears most frequently in the data set.
Let's count the occurrences of each value:

• 125: 1
• 131: 1
• 132: 1
• 133: 1
• 135: 2
• 141: 3
• 148: 2
• 154: 1
• 155: 1
• 160: 1
• 162: 1
• 165: 1
• 172: 2
• 181: 1
• 185: 1 The value 141 appears 3 times, which is more than any other value.

The results are:

• Mean: $\boxed{\text{149.3 pounds}}$
• Median: $\boxed{\text{148 pounds}}$
• Mode: $\boxed{\text{141 pounds}}$