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Three numbers are in geometric progression. Their sum is 26 and their product is 216. Find the numbers.

Mathematics

ScanSolve AI Answer

Answer

13 or 3\frac{1}{3} \text{ or } 3

6

Step-by-step solution

8 steps
  1. Identify the given information for the geometric progression.

    Let the three terms of the geometric progression be ar\frac{a}{r}, aa, and arar, where aa is the middle term and rr is the common ratio.
    The sum of the first three terms is 26:

    ar+a+ar=26(∗)\frac{a}{r} + a + ar = 26 \quad (*)

    The product of the first three terms is 216:

    ar⋅a⋅ar=216\frac{a}{r} \cdot a \cdot ar = 216
  2. Solve for aa using the product equation.

    a3=216a^3 = 216

    Take the cube root of both sides:

    a=2163a = \sqrt[3]{216} a=6a = 6
  3. Substitute the value of aa into the sum equation.

    Substitute a=6a=6 into equation (∗)(*):

    6r+6+6r=26\frac{6}{r} + 6 + 6r = 26
  4. Simplify and rearrange the equation to solve for rr.

    Subtract 6 from both sides:

    6r+6r=20\frac{6}{r} + 6r = 20

    Multiply the entire equation by rr to eliminate the fraction:

    6+6r2=20r6 + 6r^2 = 20r

    Rearrange into a standard quadratic equation form Ar2+Br+C=0Ar^2 + Br + C = 0:

    6r2−20r+6=06r^2 - 20r + 6 = 0

    Divide the entire equation by 2 to simplify:

    3r2−10r+3=03r^2 - 10r + 3 = 0
  5. Solve the quadratic equation for rr.

    Factor the quadratic equation:

    3r2−9r−r+3=03r^2 - 9r - r + 3 = 0 3r(r−3)−1(r−3)=03r(r - 3) - 1(r - 3) = 0 (3r−1)(r−3)=0(3r - 1)(r - 3) = 0

    Set each factor to zero to find the possible values for rr:

    3r−1=0  ⟹  3r=1  ⟹  r=133r - 1 = 0 \implies 3r = 1 \implies r = \frac{1}{3} r−3=0  ⟹  r=3r - 3 = 0 \implies r = 3

    The common ratio can be 13\frac{1}{3} or 3.

    The common ratio is 13 or 3\boxed{\frac{1}{3} \text{ or } 3}.

  6. Recall the difference of squares formula.

    The difference of squares formula states that x2−y2=(x−y)(x+y)x^2 - y^2 = (x - y)(x + y).

  7. Substitute the given values into the formula.

    We are given:

    x2−y2=12x^2 - y^2 = 12 x−y=2x - y = 2

    Substitute these values into the formula:

    (x−y)(x+y)=12(x - y)(x + y) = 12 (2)(x+y)=12(2)(x + y) = 12
  8. Solve for x+yx + y.

    Divide both sides by 2:

    x+y=122x + y = \frac{12}{2} x+y=6x + y = 6

    The value of x+yx + y is 6\boxed{6}.

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