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Three vectors a = 3i+4j, b = 6i+8j, c = -6i-8c. Identify which are (i) equal (ii) parallel (iii) opposite.

Mathematics

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Here are the solutions for the vector problem.

The given vectors are:

a⃗=3i⃗+4j⃗\vec{a} = 3\vec{i} + 4\vec{j} b⃗=−6i⃗+8j⃗\vec{b} = -6\vec{i} + 8\vec{j} c⃗=−6i⃗−8j⃗\vec{c} = -6\vec{i} - 8\vec{j}
  1. Identify equal vectors.

    Two vectors are equal if their corresponding components are identical.
    Comparing the components:
    a⃗=(3,4)\vec{a} = (3, 4)
    b⃗=(−6,8)\vec{b} = (-6, 8)
    c⃗=(−6,−8)\vec{c} = (-6, -8)
    No two vectors have identical components.
    Therefore, no two vectors are equal.

  2. Identify parallel vectors.

    Two vectors u⃗\vec{u} and v⃗\vec{v} are parallel if v⃗=ku⃗\vec{v} = k\vec{u} for some non-zero scalar kk. This means their corresponding components must be proportional.

    • Check a⃗\vec{a} and b⃗\vec{b}: Assume b⃗=ka⃗\vec{b} = k\vec{a}:

      −6i⃗+8j⃗=k(3i⃗+4j⃗)-6\vec{i} + 8\vec{j} = k(3\vec{i} + 4\vec{j}) −6i⃗+8j⃗=3ki⃗+4kj⃗-6\vec{i} + 8\vec{j} = 3k\vec{i} + 4k\vec{j}

      Equating the components:

      −6=3k  ⟹  k=−2-6 = 3k \implies k = -2 8=4k  ⟹  k=28 = 4k \implies k = 2

      Since the value of kk is not consistent (−2≠2-2 \neq 2), a⃗\vec{a} and b⃗\vec{b} are not parallel.

    • Check a⃗\vec{a} and c⃗\vec{c}: Assume c⃗=ka⃗\vec{c} = k\vec{a}:

      −6i⃗−8j⃗=k(3i⃗+4j⃗)-6\vec{i} - 8\vec{j} = k(3\vec{i} + 4\vec{j}) −6i⃗−8j⃗=3ki⃗+4kj⃗-6\vec{i} - 8\vec{j} = 3k\vec{i} + 4k\vec{j}

      Equating the components:

      −6=3k  ⟹  k=−2-6 = 3k \implies k = -2 −8=4k  ⟹  k=−2-8 = 4k \implies k = -2

      Since k=−2k = -2 is consistent for both components, a⃗\vec{a} and c⃗\vec{c} are parallel.

    • Check b⃗\vec{b} and c⃗\vec{c}: Assume c⃗=kb⃗\vec{c} = k\vec{b}:

      −6i⃗−8j⃗=k(−6i⃗+8j⃗)-6\vec{i} - 8\vec{j} = k(-6\vec{i} + 8\vec{j}) −6i⃗−8j⃗=−6ki⃗+8kj⃗-6\vec{i} - 8\vec{j} = -6k\vec{i} + 8k\vec{j}

      Equating the components:

      −6=−6k  ⟹  k=1-6 = -6k \implies k = 1 −8=8k  ⟹  k=−1-8 = 8k \implies k = -1

      Since the value of kk is not consistent (1≠−11 \neq -1), b⃗\vec{b} and c⃗\vec{c} are not parallel.

    Therefore, the parallel vectors are a⃗ and c⃗\boxed{\vec{a} \text{ and } \vec{c}}.

  3. Identify opposite vectors.

    Strictly, two vectors u⃗\vec{u} and v⃗\vec{v} are opposite if v⃗=−u⃗\vec{v} = -\vec{u}. This means they have the same magnitude and point in exactly opposite directions.
    First, calculate the magnitudes of the vectors:

    ∣a⃗∣=32+42=9+16=25=5|\vec{a}| = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5 ∣b⃗∣=(−6)2+82=36+64=100=10|\vec{b}| = \sqrt{(-6)^2 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10 ∣c⃗∣=(−6)2+(−8)2=36+64=100=10|\vec{c}| = \sqrt{(-6)^2 + (-8)^2} = \sqrt{36 + 64} = \sqrt{100} = 10

    For vectors to be opposite, their magnitudes must be equal. Only b⃗\vec{b} and c⃗\vec{c} have equal magnitudes.
    Let's check if c⃗=−b⃗\vec{c} = -\vec{b}:

    −b⃗=−(−6i⃗+8j⃗)=6i⃗−8j⃗-\vec{b} = -(-6\vec{i} + 8\vec{j}) = 6\vec{i} - 8\vec{j}

    Since c⃗=−6i⃗−8j⃗\vec{c} = -6\vec{i} - 8\vec{j} and −b⃗=6i⃗−8j⃗-\vec{b} = 6\vec{i} - 8\vec{j}, they are not equal. Thus, b⃗\vec{b} and c⃗\vec{c} are not opposite.
    Under the strict definition, no two vectors are opposite.

    However, "opposite" can also be interpreted as "parallel and pointing in the opposite direction" (i.e., v⃗=ku⃗\vec{v} = k\vec{u} where k<0k < 0).
    From Step 2, we found that a⃗\vec{a} and c⃗\vec{c} are parallel, with c⃗=−2a⃗\vec{c} = -2\vec{a}. Since k=−2k = -2 (which is negative), a⃗\vec{a} and c⃗\vec{c} are parallel and point in opposite directions.
    Therefore, the vectors that are parallel and point in opposite directions are a⃗ and c⃗\boxed{\vec{a} \text{ and } \vec{c}}.

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