This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
ScanSolve AI Answer
Haya, hebu tuangalie kazi yako na tutatue maswali yaliyobaki. Kutoka kwenye mahesabu yako ya awali, ujazo wa chuma kilichotumika kutengeneza bomba ni sahihi: V_iliyotumika = 495 cm^3 a) Kokotoa eneo la msalaba la chuma kwenye bomba. Step 1: Tambua rediasi ya nje na ya ndani ya bomba. Rediasi ya nje R = 3 cm. Rediasi ya ndani r = 2.3 cm. Step 2: Kokotoa eneo la msalaba la chuma. Eneo la msalaba la chuma ni tofauti kati ya eneo la duara la nje na eneo la duara la ndani. A_msalaba = R^2 - r^2 A_msalaba = (R^2 - r^2) A_msalaba = ((3 cm)^2 - (2.3 cm)^2) A_msalaba = (9 cm^2 - 5.29 cm^2) A_msalaba = (3.71 cm^2) Eneo la msalaba la chuma kwenye bomba ni 3.71 cm^2. Jibu lako la 1.16 cm^2 lilikuwa si sahihi. b) Kokotoa urefu wa bomba kwa mita, kwa sehemu mbili za desimali. Step 1: Tumia ujazo wa chuma kilichotumika na eneo la msalaba kukokotoa urefu wa bomba. Ujazo wa bomba ni sawa na ujazo wa chuma kilichotumika. V_bomba = A_msalaba × h Ambapo h ni urefu wa bomba. 495 cm^3 = 3.71 cm^2 × h Step 2: Tafuta h. Gawanya pande zote mbili kwa 3.71 cm^2: h = 495 cm^33.71 cm^2 h = (495)/(3.71) cm h ≈ 133.42318 cm Step 3: Badilisha urefu kutoka sentimita kwenda mita na uzungushe kwa sehemu mbili za desimali. Kumbuka kuwa 1 m = 100 cm. h_mita = 133.42318 cm100 cm/m h_mita ≈ 1.3342318 m Kuzungusha kwa sehemu mbili za desimali: h_mita ≈ 1.33 m Urefu wa bomba ni 1.33 m. Jibu lako la 4.27 m lilikuwa si sahihi kwa sababu lilitokana na eneo la msalaba lisilo sahihi. That's 2 down. 3 left today — send the next one.