To find matrix X such that AX = I, we need to find the inverse of matrix A, i.e., X = A^-1.

May 24, 2026Mathematics

ScanSolve AI Answer

May 24, 2026

Answer

\begin{bmatrix} 1 & 2 \ 4 & 3 \end{bmatrix}$$

To find matrix $X$ such that $AX = I$ , we need to find the inverse of matrix $A$ , i.e., $X = A^{-1}$ .

The given matrix $A$ is: $A = \begin{bmatrix} 1 & 2 \\ 4 & 3 \end{bmatrix}$

Step 1: Calculate the determinant of matrix $A$ . For a $2 \times 2$ matrix $\begin{bmatrix} a & b \\ c & d \end{bmatrix}$ , the determinant is $ad - bc$ . $\det(A) = (1)(3) - (2)(4) = 3 - 8 = -5$

Step 2: Find the adjoint of matrix $A$ . For a $2

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To find matrix X such that AX = I, we need to find the inverse of matrix A, i.e., X = A^-1.

Asked on May 24, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI AnswerAnswered on May 24, 2026

To find matrix X such that AX = I, we need to find the inverse of matrix A, i.e., X = A^-1. The given matrix A is: A = 1 & 2 \\ 4 & 3 Step 1: Calculate the determinant of matrix A. For a 2 × 2 matrix a & b \\ c & d , the determinant is ad - bc. (A) = (1)(3) - (2)(4) = 3 - 8 = -5 Step 2: Find the adjoint of matrix A. For a $2