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To find the mean deviation, we first need to calculate the mean (x) of the given ages, and then find the average of the absolute differences between each age and the mean.

Mathematics

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Answer

6.34375

Step-by-step solution

4 steps

To find the mean deviation, we first need to calculate the mean (xˉ\bar{x}) of the given ages, and then find the average of the absolute differences between each age and the mean.

The ages are: 17,11,31,18,25,29,13,1517, 11, 31, 18, 25, 29, 13, 15.
The number of observations is N=8N=8.

  1. Calculate the mean (xˉ\bar{x}).

    The mean is the sum of all ages divided by the number of ages.

    xˉ=17+11+31+18+25+29+13+158\bar{x} = \frac{17 + 11 + 31 + 18 + 25 + 29 + 13 + 15}{8} xˉ=1598\bar{x} = \frac{159}{8} xˉ=19.875\bar{x} = 19.875
  2. Calculate the absolute deviation of each age from the mean, ∣xi−xˉ∣|x_i - \bar{x}|.

    • ∣17−19.875∣=∣−2.875∣=2.875|17 - 19.875| = |-2.875| = 2.875
    • ∣11−19.875∣=∣−8.875∣=8.875|11 - 19.875| = |-8.875| = 8.875
    • ∣31−19.875∣=∣11.125∣=11.125|31 - 19.875| = |11.125| = 11.125
    • ∣18−19.875∣=∣−1.875∣=1.875|18 - 19.875| = |-1.875| = 1.875
    • ∣25−19.875∣=∣5.125∣=5.125|25 - 19.875| = |5.125| = 5.125
    • ∣29−19.875∣=∣9.125∣=9.125|29 - 19.875| = |9.125| = 9.125
    • ∣13−19.875∣=∣−6.875∣=6.875|13 - 19.875| = |-6.875| = 6.875
    • ∣15−19.875∣=∣−4.875∣=4.875|15 - 19.875| = |-4.875| = 4.875
  3. Calculate the sum of the absolute deviations.

    ∑∣xi−xˉ∣=2.875+8.875+11.125+1.875+5.125+9.125+6.875+4.875\sum |x_i - \bar{x}| = 2.875 + 8.875 + 11.125 + 1.875 + 5.125 + 9.125 + 6.875 + 4.875 ∑∣xi−xˉ∣=50.75\sum |x_i - \bar{x}| = 50.75
  4. Calculate the mean deviation.

    The mean deviation is the sum of the absolute deviations divided by the number of observations.

    Mean Deviation=∑∣xi−xˉ∣N\text{Mean Deviation} = \frac{\sum |x_i - \bar{x}|}{N} Mean Deviation=50.758\text{Mean Deviation} = \frac{50.75}{8} Mean Deviation=6.34375\text{Mean Deviation} = 6.34375

    The final answer is 6.34375.

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