To repair a stretch of a road, 4 people can do it in 18 days. How many people are required to do it in 12 days? 10. In Kong'oo's farm, the number of goats is less than or equal to the number of sheep

Here are the solutions to the problems: 9. To repair a stretch of a road Step 1: Identify the relationship between the number of people and the time taken. This is an inverse proportion problem. The total amount of work is constant. Let P_1 be the initial number of people and D_1 be the initial number of days. Let P_2 be the new number of people and D_2 be the new number of days. The relationship is given by P_1 D_1 = P_2 D_2. Step 2: Substitute the given values into the equation. We have P_1 = 4 people, D_1 = 18 days, and D_2 = 12 days. We need to find P_2. 4 × 18 = P_2 × 12 Step 3: Solve for P_2. 72 = 12 P_2 Divide both sides by 12: P_2 = (72)/(12) P_2 = 6 To complete the work in 12 days, 6 people will be required. 10. In Kong'oo's farm a) Form a compound inequality Step 1: Identify the given information. Number of cows = 3 Number of sheep = 9 Let x represent the number of goats. Step 2: Translate the conditions into inequalities. "The number of goats could be less than or equal to that of sheep" means x 9. "but more than that of cows" means x > 3. Step 3: Combine the two inequalities into a compound inequality. The compound inequality is 3 < x 9. b) Represent the inequality formed on a number line Step 1: Draw a number line and mark the relevant numbers. Step 2: For x > 3, place an open circle at 3 (since 3 is not included). Step 3: For x 9, place a closed circle at 9 (since 9 is included). Step 4: Draw a line segment connecting the open circle at 3 and the closed circle at 9 to show all possible values of x. ` <---------------------------------------------------------------------> ... -1 0 1 2 (3) 4 5 6 7 8 [9] 10 11 12 ... ^ ^ | | Open circle at 3 Closed circle at 9 ` Last free one today — make it count tomorrow, or type /upgrade for unlimited.