We read your photo as:

A team of 3 tractors, each working 8 hours a day, can plough a field in 5 days. How many days would it take 2 tractors, each working 10 hours a day, to plough the same field? Also, answer questions 11

Mathematics

ScanSolve AI Answer

Step-by-step solution

6 steps

here are the solutions to the problems.

:

  1. Calculate the total work units for the initial scenario.

    The work done is proportional to the number of tractors, hours per day, and number of days.
    Initial work units = 3 tractors×8 hours/day×5 days=120 tractor-hours3 \text{ tractors} \times 8 \text{ hours/day} \times 5 \text{ days} = 120 \text{ tractor-hours}.

  2. Set up the equation for the new scenario.

    Let DD be the number of days for the new scenario.
    New work units = 2 tractors×10 hours/day×D days=20D tractor-hours2 \text{ tractors} \times 10 \text{ hours/day} \times D \text{ days} = 20D \text{ tractor-hours}.

  3. Equate the work units and solve for DD.

    Since the same field is being ploughed, the total work units are equal.

    120=20D120 = 20D D=12020D = \frac{120}{20} D=6D = 6

    It would take 2 such tractors, working 10 hours a day, 6 days\boxed{\text{6 days}} to plough the same field.

    :
    The problem asks to convert Euros to Kenyan Shillings and then remaining Kenyan Shillings to Japanese Yen. However, the provided table only lists exchange rates for US Dollars and UK Pounds. The exchange rates for Euros to Kenyan Shillings and Kenyan Shillings to Japanese Yen are not provided in the given information. Therefore, this problem cannot be solved with the information available.

    :

  4. Calculate the total time taken by the team.

    The times for each athlete are 45 sec, 43 sec, 44 sec, and 45 sec.
    Total time = 45+43+44+45=177 seconds45 + 43 + 44 + 45 = 177 \text{ seconds}.

  5. Convert the total time into minutes and seconds.

    177 seconds=2 minutes and 57 seconds177 \text{ seconds} = 2 \text{ minutes and } 57 \text{ seconds}

    (Since 177=2×60+57177 = 2 \times 60 + 57)

  6. Add the total race time to the start time.

    The race started at 1:35:31 p.m.
    Add 2 minutes and 57 seconds to this time.

    Start time=1:35:31 p.m.Add minutes=35+2=37Add seconds=31+57=88\begin{align*} \text{Start time} &= 1:35:31 \text{ p.m.} \\ \text{Add minutes} &= 35 + 2 = 37 \\ \text{Add seconds} &= 31 + 57 = 88 \end{align*}

    So the time is 1:37:88 p.m.
    Since there are 60 seconds in a minute, convert 88 seconds:

    88 seconds=1 minute and 28 seconds88 \text{ seconds} = 1 \text{ minute and } 28 \text{ seconds}

    Add this 1 minute to the minutes column:

    37 minutes+1 minute=38 minutes37 \text{ minutes} + 1 \text{ minute} = 38 \text{ minutes}

    The completion time is 1:38:28 p.m.
    The team completed the race at 1:38:28 p.m.\boxed{\text{1:38:28 p.m.}}.

Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp