A farmer has 6 tractors, each ploughing 120 hectares a day. They complete a field in 4 days. If 2 tractors are removed, how many days will it take the remaining tractors to finish the field? What is t

Initially, there are 6 tractors, and each ploughs 120 hectares a day. They complete the field in 4 days.
Total hectares ploughed per day by 6 tractors:

$$6 \text{ tractors} \times 120 \frac{\text{hectares}}{\text{tractor} \cdot \text{day}} = 720 \frac{\text{hectares}}{\text{day}}$$

Total area of the field:

$$720 \frac{\text{hectares}}{\text{day}} \times 4 \text{ days} = 2880 \text{ hectares}$$

Two tractors were moved, so the remaining tractors are:

$$6 - 2 = 4 \text{ tractors}$$

The remaining 4 tractors plough the same 2880-hectare field in 5 days.
Total hectares ploughed per day by 4 tractors:

$$\frac{2880 \text{ hectares}}{5 \text{ days}} = 576 \frac{\text{hectares}}{\text{day}}$$

Divide the total hectares ploughed per day by the number of remaining tractors:

$$\frac{576 \frac{\text{hectares}}{\text{day}}}{4 \text{ tractors}} = 144 \frac{\text{hectares}}{\text{tractor} \cdot \text{day}}$$

One tractor would plough 144 hectares a day.

The final answer is $\text{144 HECTARES}$.