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To solve the quadratic equation ax² + bx + c = 0 using the quadratic formula, also known as the "almighty formula". The quadratic formula is given by:

Mathematics

ScanSolve AI Answer

Step-by-step solution

6 steps

The problem asks to solve the quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 using the quadratic formula, also known as the "almighty formula". The quadratic formula is given by:

x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

We need to consider the discriminant, Δ=b2−4ac\Delta = b^2 - 4ac, to determine the nature of the roots:

  • If Δ>0\Delta > 0, there are two distinct real roots.
  • If Δ=0\Delta = 0, there is one real root (a repeated root).
  • If Δ<0\Delta < 0, there are two complex conjugate roots.

We also need to handle the case where a=0a=0, as the equation becomes linear or trivial.

1. Pseudocode Program

  1. Start the program.

  2. Declare variables a, b, c for coefficients, discriminant, root1, root2, realPart, imaginaryPart.

  3. Prompt the user to input the values for a, b, and c.

  4. Read the values for a, b, and c.

  5. Check if a is zero.

    *   If `a == 0`:
        *   If `b == 0`:
            *   If `c == 0`:
                *   Output "Infinite solutions (0 = 0)".
            *   Else (`c != 0`):
                *   Output "No solution (e.g., 5 = 0, which is false)".
        *   Else (`b != 0`):
            *   Calculate `root = -c / b`.
            *   Output "This is a linear equation. Root = ", `root`.
    *   Else (`a != 0`, it's a quadratic equation):
        *   Calculate `discriminant = b*b - 4*a*c`.
        *   If `discriminant > 0`:
            *   Calculate `root1 = (-b + SQRT(discriminant)) / (2*a)`.
            *   Calculate `root2 = (-b - SQRT(discriminant)) / (2*a)`.
            *   Output "Two distinct real roots: ", `root1`, " and ", `root2`.
        *   Else If `discriminant == 0`:
            *   Calculate `root1 = -b / (2*a)`.
            *   Output "One real root (repeated): ", `root1`.
        *   Else (`discriminant < 0`):
            *   Calculate `realPart = -b / (2*a)`.
            *   Calculate `imaginaryPart = SQRT(ABS(discriminant)) / (2*a)`.
            *   Output "Two complex conjugate roots: ", `realPart`, " + ", `imaginaryPart`, "i", " and ", `realPart`, " - ", `imaginaryPart`, "i`.
    
  6. End the program.

    2. C++ Program

    #include <iostream> // Required for input/output operations (cin, cout)
    #include <cmath>    // Required for mathematical functions like sqrt() and abs()
    
    int main() {
        // Declare variables to store the coefficients
        double a, b, c;
    
        // Prompt the user to enter the coefficients
        std::cout << "Enter coefficient a: ";
        std::cin >> a;
        std::cout << "Enter coefficient b: ";
        std::cin >> b;
        std::cout << "Enter coefficient c: ";
        std::cin >> c;
    
        // Check if 'a' is zero to handle linear or trivial equations
        if (a == 0) {
            if (b == 0) {
                if (c == 0) {
                    // Case: 0x^2 + 0x + 0 = 0 => 0 = 0 (Infinite solutions)
                    std::cout << "Infinite solutions (0 = 0)." << std::endl;
                } else {
                    // Case: 0x^2 + 0x + c = 0 (where c != 0) => c = 0 (No solution)
                    std::cout << "No solution (e.g., " << c << " = 0, which is false)." << std::endl;
                }
            } else {
                // Case: 0x^2 + bx + c = 0 (where b != 0) => bx + c = 0 (Linear equation)
                double root = -c / b;
                std::cout << "This is a linear equation: " << b << "x + " << c << " = 0." << std::endl;
                std::cout << "Root = " << root << std::endl;
            }
        } else {
            // If 'a' is not zero, it's a quadratic equation.
            // Calculate the discriminant
            double discriminant = b * b - 4 * a * c;
    
            // Determine the nature of the roots based on the discriminant
            if (discriminant > 0) {
                // Two distinct real roots
                double root1 = (-b + sqrt(discriminant)) / (2 * a);
                double root2 = (-b - sqrt(discriminant)) / (2 * a);
                std::cout << "Roots are real and different." << std::endl;
                std::cout << "Root 1 = " << root1 << std::endl;
                std::cout << "Root 2 = " << root2 << std::endl;
            } else if (discriminant == 0) {
                // One real root (repeated)
                double root1 = -b / (2 * a);
                std::cout << "Roots are real and same." << std::endl;
                std::cout << "Root 1 = Root 2 = " << root1 << std::endl;
            } else {
                // Two complex conjugate roots
                double realPart = -b / (2 * a);
                double imaginaryPart = sqrt(std::abs(discriminant)) / (2 * a);
                std::cout << "Roots are complex and different." << std::endl;
                std::cout << "Root 1 = " << realPart << " + " << imaginaryPart << "i" << std::endl;
                std::cout << "Root 2 = " << realPart << " - " << imaginaryPart << "i" << std::endl;
            }
        }
    
        return 0; // Indicate successful program execution
    }
    
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