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To solve the quadratic equation ax² + bx + c = 0 using the quadratic formula, also known as the "almighty formula". The quadratic formula is given by:
Mathematics
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Step-by-step solution
6 stepsThe problem asks to solve the quadratic equation using the quadratic formula, also known as the "almighty formula". The quadratic formula is given by:
We need to consider the discriminant, , to determine the nature of the roots:
- If , there are two distinct real roots.
- If , there is one real root (a repeated root).
- If , there are two complex conjugate roots.
We also need to handle the case where , as the equation becomes linear or trivial.
1. Pseudocode Program
Start the program.
Declare variables
a,b,cfor coefficients,discriminant,root1,root2,realPart,imaginaryPart.Prompt the user to input the values for
a,b, andc.Read the values for
a,b, andc.Check if
ais zero.* If `a == 0`: * If `b == 0`: * If `c == 0`: * Output "Infinite solutions (0 = 0)". * Else (`c != 0`): * Output "No solution (e.g., 5 = 0, which is false)". * Else (`b != 0`): * Calculate `root = -c / b`. * Output "This is a linear equation. Root = ", `root`. * Else (`a != 0`, it's a quadratic equation): * Calculate `discriminant = b*b - 4*a*c`. * If `discriminant > 0`: * Calculate `root1 = (-b + SQRT(discriminant)) / (2*a)`. * Calculate `root2 = (-b - SQRT(discriminant)) / (2*a)`. * Output "Two distinct real roots: ", `root1`, " and ", `root2`. * Else If `discriminant == 0`: * Calculate `root1 = -b / (2*a)`. * Output "One real root (repeated): ", `root1`. * Else (`discriminant < 0`): * Calculate `realPart = -b / (2*a)`. * Calculate `imaginaryPart = SQRT(ABS(discriminant)) / (2*a)`. * Output "Two complex conjugate roots: ", `realPart`, " + ", `imaginaryPart`, "i", " and ", `realPart`, " - ", `imaginaryPart`, "i`.End the program.
2. C++ Program
#include <iostream> // Required for input/output operations (cin, cout) #include <cmath> // Required for mathematical functions like sqrt() and abs() int main() { // Declare variables to store the coefficients double a, b, c; // Prompt the user to enter the coefficients std::cout << "Enter coefficient a: "; std::cin >> a; std::cout << "Enter coefficient b: "; std::cin >> b; std::cout << "Enter coefficient c: "; std::cin >> c; // Check if 'a' is zero to handle linear or trivial equations if (a == 0) { if (b == 0) { if (c == 0) { // Case: 0x^2 + 0x + 0 = 0 => 0 = 0 (Infinite solutions) std::cout << "Infinite solutions (0 = 0)." << std::endl; } else { // Case: 0x^2 + 0x + c = 0 (where c != 0) => c = 0 (No solution) std::cout << "No solution (e.g., " << c << " = 0, which is false)." << std::endl; } } else { // Case: 0x^2 + bx + c = 0 (where b != 0) => bx + c = 0 (Linear equation) double root = -c / b; std::cout << "This is a linear equation: " << b << "x + " << c << " = 0." << std::endl; std::cout << "Root = " << root << std::endl; } } else { // If 'a' is not zero, it's a quadratic equation. // Calculate the discriminant double discriminant = b * b - 4 * a * c; // Determine the nature of the roots based on the discriminant if (discriminant > 0) { // Two distinct real roots double root1 = (-b + sqrt(discriminant)) / (2 * a); double root2 = (-b - sqrt(discriminant)) / (2 * a); std::cout << "Roots are real and different." << std::endl; std::cout << "Root 1 = " << root1 << std::endl; std::cout << "Root 2 = " << root2 << std::endl; } else if (discriminant == 0) { // One real root (repeated) double root1 = -b / (2 * a); std::cout << "Roots are real and same." << std::endl; std::cout << "Root 1 = Root 2 = " << root1 << std::endl; } else { // Two complex conjugate roots double realPart = -b / (2 * a); double imaginaryPart = sqrt(std::abs(discriminant)) / (2 * a); std::cout << "Roots are complex and different." << std::endl; std::cout << "Root 1 = " << realPart << " + " << imaginaryPart << "i" << std::endl; std::cout << "Root 2 = " << realPart << " - " << imaginaryPart << "i" << std::endl; } } return 0; // Indicate successful program execution }
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