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Calculate the total amount payable by the Reddy family for their household water usage of 33 kl in February 2026. The Reddy household paid R1 047,19 (VAT inclusive) for water consumption in March 2025. Determine the number of kilolitres of water used by the household.

Mathematics

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Answer

R1554.43\text{R}1554.43

25.97 kL25.97 \text{ kL}

Step-by-step solution

10 steps

Here are the calculations for the water consumption questions:

4.2.1 Calculate the total amount payable by the Reddy family for their household water usage of 33 kL in February 2026.

  1. Calculate the cost of water consumption per block (excluding VAT).

    The total consumption is 33 kL. We break this down according to the tariff blocks:

    • Block 1 (0-6 kL): 6 kL×R0.00/kL=R0.006 \text{ kL} \times \text{R}0.00/\text{kL} = \text{R}0.00
    • Block 2 (6-10 kL): 4 kL×R29.84/kL=R119.364 \text{ kL} \times \text{R}29.84/\text{kL} = \text{R}119.36
    • Block 3 (10-15 kL): 5 kL×R31.15/kL=R155.755 \text{ kL} \times \text{R}31.15/\text{kL} = \text{R}155.75
    • Block 4 (15-20 kL): 5 kL×R43.67/kL=R218.355 \text{ kL} \times \text{R}43.67/\text{kL} = \text{R}218.35
    • Block 5 (20-30 kL): 10 kL×R60.36/kL=R603.6010 \text{ kL} \times \text{R}60.36/\text{kL} = \text{R}603.60
    • Block 6 (30-40 kL): The remaining consumption is 33 kL−30 kL=3 kL33 \text{ kL} - 30 \text{ kL} = 3 \text{ kL}. 3 kL×R66.01/kL=R198.033 \text{ kL} \times \text{R}66.01/\text{kL} = \text{R}198.03
  2. Calculate the total water consumption cost excluding VAT.

    Total water cost (excl. VAT)=R0.00+R119.36+R155.75+R218.35+R603.60+R198.03=R1295.09\text{Total water cost (excl. VAT)} = \text{R}0.00 + \text{R}119.36 + \text{R}155.75 + \text{R}218.35 + \text{R}603.60 + \text{R}198.03 = \text{R}1295.09
  3. Add 15% VAT to the water consumption cost.

    VAT amount=R1295.09×0.15=R194.2635\text{VAT amount} = \text{R}1295.09 \times 0.15 = \text{R}194.2635 Water cost (incl. VAT)=R1295.09+R194.2635=R1489.3535\text{Water cost (incl. VAT)} = \text{R}1295.09 + \text{R}194.2635 = \text{R}1489.3535
  4. Add the fixed monthly management levy (VAT inclusive).

    The fixed monthly management levy is R65.08 (including 15% VAT).

    Total payable=R1489.3535+R65.08=R1554.4335\text{Total payable} = \text{R}1489.3535 + \text{R}65.08 = \text{R}1554.4335
  5. Round the total payable amount to two decimal places.

    Total payable=R1554.43\text{Total payable} = \text{R}1554.43

    The total amount payable by the Reddy family is R1554.43\boxed{\text{R}1554.43}.

    4.2.2 The Reddy household paid R1 047.19 (VAT inclusive) for water consumption in March 2025. Determine the number of kilolitres of water used by the household.

  6. Subtract the fixed monthly management levy to find the water consumption cost (VAT inclusive).

    The total paid was R1 047.19, and the fixed levy is R65.08 (VAT inclusive).

    Water consumption cost (incl. VAT)=R1047.19−R65.08=R982.11\text{Water consumption cost (incl. VAT)} = \text{R}1047.19 - \text{R}65.08 = \text{R}982.11
  7. Calculate the water consumption cost excluding VAT.

    The VAT rate is 15%.

    Water consumption cost (excl. VAT)=R982.111+0.15=R982.111.15=R854.00869...≈R854.01\text{Water consumption cost (excl. VAT)} = \frac{\text{R}982.11}{1 + 0.15} = \frac{\text{R}982.11}{1.15} = \text{R}854.00869... \approx \text{R}854.01
  8. Determine the kilolitres used by working backwards through the tariff blocks.

    • Block 1 (0-6 kL): Cost = 6 kL×R0.00/kL=R0.006 \text{ kL} \times \text{R}0.00/\text{kL} = \text{R}0.00. Remaining cost = R854.01. Current kL = 6.
    • Block 2 (6-10 kL): Cost = 4 kL×R29.84/kL=R119.364 \text{ kL} \times \text{R}29.84/\text{kL} = \text{R}119.36. Remaining cost = R854.01−R119.36=R734.65\text{R}854.01 - \text{R}119.36 = \text{R}734.65. Current kL = 6+4=106+4=10.
    • Block 3 (10-15 kL): Cost = 5 kL×R31.15/kL=R155.755 \text{ kL} \times \text{R}31.15/\text{kL} = \text{R}155.75. Remaining cost = R734.65−R155.75=R578.90\text{R}734.65 - \text{R}155.75 = \text{R}578.90. Current kL = 10+5=1510+5=15.
    • Block 4 (15-20 kL): Cost = 5 kL×R43.67/kL=R218.355 \text{ kL} \times \text{R}43.67/\text{kL} = \text{R}218.35. Remaining cost = R578.90−R218.35=R360.55\text{R}578.90 - \text{R}218.35 = \text{R}360.55. Current kL = 15+5=2015+5=20.
    • Block 5 (20-30 kL): The remaining cost (R360.55) is less than the full cost of Block 5 (10 kL×R60.36/kL=R603.6010 \text{ kL} \times \text{R}60.36/\text{kL} = \text{R}603.60), so the consumption falls within this block. kL in Block 5=R360.55R60.36/kL=5.97332669... kL\text{kL in Block 5} = \frac{\text{R}360.55}{\text{R}60.36/\text{kL}} = 5.97332669... \text{ kL}
  9. Calculate the total kilolitres used.

    Total kL=6 kL+4 kL+5 kL+5 kL+5.97332669 kL=25.97332669 kL\text{Total kL} = 6 \text{ kL} + 4 \text{ kL} + 5 \text{ kL} + 5 \text{ kL} + 5.97332669 \text{ kL} = 25.97332669 \text{ kL}
  10. Round the total kilolitres to two decimal places.

    Total kL≈25.97 kL\text{Total kL} \approx 25.97 \text{ kL}

    The number of kilolitres of water used by the household is 25.97 kL\boxed{25.97 \text{ kL}}.

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