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Calculate the total cost of water consumption for 17 kℓ per the tiered pricing structure.

Economics

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Answers

5 parts
a

4,5 kℓ\text{4,5 k}\ell

b

STEP 3\text{STEP 3}

c

R 439,91\text{R } 439,91

d

R 307,94\text{R } 307,94

e

R 747,85\text{R } 747,85

Step-by-step solution

7 steps

Part a· 2 steps

  1. Determine the range for STEP 2.

    STEP 2 covers water consumption from >6 kℓ> 6 \text{ k}\ell up to 10,5 kℓ10,5 \text{ k}\ell.

  2. Calculate the number of kiloliters in STEP 2.

    Kiloliters in STEP 2=10,5 kℓ−6 kℓ=4,5 kℓ\text{Kiloliters in STEP 2} = 10,5 \text{ k}\ell - 6 \text{ k}\ell = 4,5 \text{ k}\ell

    The number of kiloliters in STEP 2 is 4,5 kℓ\boxed{\text{4,5 k}\ell}.

Part b

STEP 3\text{STEP 3}

  1. Identify the consumption range for 17 kℓ17 \text{ k}\ell.

    • STEP 1: 0≤6 kℓ0 \le 6 \text{ k}\ell
    • STEP 2: >6≤10,5 kℓ> 6 \le 10,5 \text{ k}\ell
    • STEP 3: >10,5≤35 kℓ> 10,5 \le 35 \text{ k}\ell
    • STEP 4: >35 kℓ> 35 \text{ k}\ell Since 17 kℓ17 \text{ k}\ell is greater than 10,5 kℓ10,5 \text{ k}\ell but less than or equal to 35 kℓ35 \text{ k}\ell, it falls within the range of STEP 3. The last step charged for 17 kℓ17 \text{ k}\ell is STEP 3\boxed{\text{STEP 3}}.

Part c

R 439,91\text{R } 439,91

  1. Calculate the cost for each consumption step for 17 kℓ17 \text{ k}\ell.

    • For STEP 1 (0 kℓ0 \text{ k}\ell to 6 kℓ6 \text{ k}\ell): Volume=6 kℓ\text{Volume} = 6 \text{ k}\ell Rate=R 17,51/kℓ\text{Rate} = \text{R } 17,51/\text{k}\ell Cost1=6 kℓ×R 17,51/kℓ=R 105,06\text{Cost}_1 = 6 \text{ k}\ell \times \text{R } 17,51/\text{k}\ell = \text{R } 105,06
    • For STEP 2 (>6 kℓ> 6 \text{ k}\ell to 10,5 kℓ10,5 \text{ k}\ell): Volume=10,5 kℓ−6 kℓ=4,5 kℓ\text{Volume} = 10,5 \text{ k}\ell - 6 \text{ k}\ell = 4,5 \text{ k}\ell Rate=R 24,39/kℓ\text{Rate} = \text{R } 24,39/\text{k}\ell Cost2=4,5 kℓ×R 24,39/kℓ=R 109,755\text{Cost}_2 = 4,5 \text{ k}\ell \times \text{R } 24,39/\text{k}\ell = \text{R } 109,755
    • For STEP 3 (>10,5 kℓ> 10,5 \text{ k}\ell to 17 kℓ17 \text{ k}\ell): Volume=17 kℓ−10,5 kℓ=6,5 kℓ\text{Volume} = 17 \text{ k}\ell - 10,5 \text{ k}\ell = 6,5 \text{ k}\ell Rate=R 34,63/kℓ\text{Rate} = \text{R } 34,63/\text{k}\ell Cost3=6,5 kℓ×R 34,63/kℓ=R 225,095\text{Cost}_3 = 6,5 \text{ k}\ell \times \text{R } 34,63/\text{k}\ell = \text{R } 225,095
  2. Calculate the total water bill.

    Total water bill=Cost1+Cost2+Cost3\text{Total water bill} = \text{Cost}_1 + \text{Cost}_2 + \text{Cost}_3 Total water bill=R 105,06+R 109,755+R 225,095\text{Total water bill} = \text{R } 105,06 + \text{R } 109,755 + \text{R } 225,095 Total water bill=R 439,91\text{Total water bill} = \text{R } 439,91

    The Adams family has to pay R 439,91\boxed{\text{R } 439,91} for the 17 kℓ17 \text{ k}\ell of water used.

Part d

R 307,94\text{R } 307,94

  1. Calculate the sewerage removal charge.

    The sewerage removal is calculated at a rate of 70%70\% of the total water bill.

    Sewerage charge=70%×Total water bill\text{Sewerage charge} = 70\% \times \text{Total water bill} Sewerage charge=0,70×R 439,91\text{Sewerage charge} = 0,70 \times \text{R } 439,91 Sewerage charge=R 307,937\text{Sewerage charge} = \text{R } 307,937

    Rounding to two decimal places:

    Sewerage charge=R 307,94\text{Sewerage charge} = \text{R } 307,94

    They were charged R 307,94\boxed{\text{R } 307,94} for the sewerage.

Part e

R 747,85\text{R } 747,85

  1. Calculate the total water and sewerage bill.

    Total bill=Total water bill+Sewerage charge\text{Total bill} = \text{Total water bill} + \text{Sewerage charge} Total bill=R 439,91+R 307,94\text{Total bill} = \text{R } 439,91 + \text{R } 307,94 Total bill=R 747,85\text{Total bill} = \text{R } 747,85

    Their total water and sewerage bill was R 747,85\boxed{\text{R } 747,85}.

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