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Determine the chargeable water consumption.

Economics

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3 parts
3.1

R144\text{R144}

3.2

R113.92\text{R113.92}

3.3

R284.49\text{R284.49}

Step-by-step solution

9 steps

here are the solutions to Question 3:

Part 3.1· 3 steps

Mrs Mabaspaced is a registered resident and she used 14 kl of water for the month of August 2022 calculate her water bill excluding VAT.

  1. Determine the chargeable water consumption.

    As a registered indigent, Mrs Mabaspaced receives 6 kl free water.

    Chargeable_consumption=14 kl−6 kl=8 klChargeable\_consumption = 14 \text{ kl} - 6 \text{ kl} = 8 \text{ kl}

  2. Identify the tariff for the chargeable consumption from the "Mogale City Approved Tariffs July (2021/2022)" table.

    The 8 kl falls into the 7 - 15 kl block, which has a tariff of R18 per kl.

  3. Calculate the total water bill.

    Water_bill=8 kl×R18/klWater\_bill = 8 \text{ kl} \times \text{R}18/\text{kl} Water_bill=R144Water\_bill = \boxed{\text{R144}}

Part 3.2

R113.92\text{R113.92}

Write down the fixed monthly electricity cost for the prepaid system in Rand.

  1. Identify the basic charge from the "Polokwane Local municipality 2021 tariff for prepaid electricity" table.

    The basic charge is 11392 cents.

  2. Convert cents to Rand.

    Fixed_cost=11392 cents100 cents/RandFixed\_cost = \frac{11392 \text{ cents}}{100 \text{ cents/Rand}} Fixed_cost=R113.92Fixed\_cost = \boxed{\text{R113.92}}

Part 3.3

R284.49\text{R284.49}

If a household uses 196 kWh of electricity in a month, how much would they pay for their electricity consumption, excluding VAT?

  1. Calculate the cost for the first block of consumption (0 – 50 units).

    CostBlock1=50 kWh×118.24 c/kWhCost_{Block1} = 50 \text{ kWh} \times 118.24 \text{ c/kWh} CostBlock1=5912 centsCost_{Block1} = 5912 \text{ cents}

  2. Calculate the remaining consumption and its cost for the next block.

    Remaining consumption = 196 kWh−50 kWh=146 kWh196 \text{ kWh} - 50 \text{ kWh} = 146 \text{ kWh}.
    This falls into Block 2 (51 – 350 units) at 154.36 c/kWh.

    CostBlock2=146 kWh×154.36 c/kWhCost_{Block2} = 146 \text{ kWh} \times 154.36 \text{ c/kWh} CostBlock2=22536.56 centsCost_{Block2} = 22536.56 \text{ cents}

  3. Calculate the total electricity consumption cost in cents.

    Total_costcents=CostBlock1+CostBlock2Total\_cost_{cents} = Cost_{Block1} + Cost_{Block2} Total_costcents=5912 cents+22536.56 centsTotal\_cost_{cents} = 5912 \text{ cents} + 22536.56 \text{ cents} Total_costcents=28448.56 centsTotal\_cost_{cents} = 28448.56 \text{ cents}

  4. Convert the total cost from cents to Rand.

    Total_costRand=28448.56 cents100 cents/RandTotal\_cost_{Rand} = \frac{28448.56 \text{ cents}}{100 \text{ cents/Rand}} Total_costRand=R284.49Total\_cost_{Rand} = \boxed{\text{R284.49}}
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